CODEWITHSUNDEEP
ruby-on-railsrubystringextractdelimiter
Kendall Weihe
Kendall Weihe

Reputation: 193

Ruby extract part of string

I have the following string ...

CN=KendallLDAPTEST Weihe,OU=CORPUSERS,OU=CORP,DC=int,DC=appriss,DC=com

and I need to extract KendallLDAPTEST Weihe

in other words I need to extract all string data between the first = and the first ,

Upvotes: 0

Views: 4956

Answers (4)

Farhad Hemmati
Farhad Hemmati

Reputation: 92

If the text you are trying to capture is always appearing on the same index you can use this:

the_text[3...22]

Upvotes: 0

the Tin Man
the Tin Man

Reputation: 160551

I'd use:

str = "CN=KendallLDAPTEST Weihe,OU=CORPUSERS,OU=CORP,DC=int,DC=appriss,DC=com"
str[/=([^,]+)/, 1] # => "KendallLDAPTEST Weihe"

By default the regular expression will find the first match then stop. This simply finds the first =, then captures all characters that are not , until the first ',' and returns it.

Upvotes: 1

nextstep
nextstep

Reputation: 1460

Tested, works

Using regex:

str = "CN=KendallLDAPTESTWeihe,OU=CORPUSERS,OU=CORP,DC=int,DC=appriss,DC=com"

str[/\=(.*?),/,1]

For anyone re-using this, replace both instances of here with the characters you want to find the text in between:

[/\here(.*?)here/,1]

Upvotes: 9

user229044
user229044

Reputation: 239311

You can simply break the string apart using split on , to first produce an array of key=value pairs, and then split those pairs on =.

str = 'CN=KendallLDAPTEST Weihe,OU=CORPUSERS,OU=CORP,DC=int,DC=appriss,DC=com'

pairs = str.split(',').map { |pair| pair.split('=') }
# => [["CN", "KendallLDAPTEST Weihe"], ["OU", "CORPUSERS"], ["OU", "CORP"], ["DC", "int"], ["DC", "appriss"], ["DC", "com"]]

pairs.first[1]
# => "KendallLDAPTEST Weihe"

This is somewhat naive in that it will not work if any of your data contains escaped = or , characters.

Upvotes: 1

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