CODEWITHSUNDEEP
linuxbashshell
PRK
PRK

Reputation: 431

How to print file/directory details using ls and AWK?

I am trying to print the output as below using the command:

ls -l| awk '/777/{print $0}'

or

ls -l| awk '/0777/{print $0}'

But it does not print anything. O/P should be like, 

drwxrwxrwx  2 sbcoper sbcprd   4096 Apr 20  2015 work

(I am using 0777 or 777 because of find . -type f -perm 0777)

Upvotes: 0

Views: 210

Answers (1)

joshbooks
joshbooks

Reputation: 489

you've got the right idea, but 777 is the octal representation of permissions, and with this you're looking at the output of ls, which lists permissions as a string, like "drwxrwxrwx", so a simple modification of your command would work nicely, ls -l | awk '/rwxrwxrwx/{print $0}'

Upvotes: 2

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