CODEWITHSUNDEEP
javaspringspring-mvcapplicationcontext
Alexandr
Alexandr

Reputation: 127

How to invoke java method with a few parameters inside spring app context xml file

I try to configure my spring app. And I need to define property placeholder like this:

<context:property-placeholder
        location="classpath:ov.properties,file:#{appServerUrl.replaceFirst('regexp','')}/test.properties"
        ignore-resource-not-found="true" />

But in result I have org.springframework.expression.ParseException: Expression 'file:#{appServerUrl.replaceFirst(''' @ 5: No ending suffix '}' for expression starting at character 5 If I invoke java method with one parameter only or without parameters, it works correctly. What's wrong? Thank you for reply.

Upvotes: 2

Views: 1289

Answers (1)

hzpz
hzpz

Reputation: 7911

The parser for the <context:property-placeholder/> elements first splits the value of the location attribute using StringUtils.commaDelimitedListToStringArray(String). That is why is splits your second location in two.

To circumvent that, you could define a String bean with the value of your second location:

<bean name="testPropertiesLocation" class="java.lang.String">
    <constructor-arg value="file:#{appServerUrl.replaceFirst('regexp','')}/test.properties" />
</bean>

Then use it like this:

<context:property-placeholder
        location="classpath:ov.properties,#{testPropertiesLocation}"
        ignore-resource-not-found="true" />

Upvotes: 1

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