CODEWITHSUNDEEP
javaregex
sshet
sshet

Reputation: 1160

Spilt string and match end of string with enum values

I have one string which i need to divide into two parts using regex

String string = "2pbhk";

This string i need to divide into 2p and bhk

More over second part should always be bhk or rk, as strings can be one of 1bhk, 5pbhk etc

I have tried 

String pattern = ([^-])([\\D]*);

Upvotes: 1

Views: 944

Answers (4)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 627086

In case you are looking to split strings that end with rk or bhk but not necessarily at the end of the string (i.e. at the word boundaries), you need to use a regex with \\b:

String[] arr = "5ddddddpbhk".split("(?=(?:rk|bhk)\\b)");
System.out.println(Arrays.toString(arr));

If you want to allow splitting inside a longer string, remove the \\b.

If you only split individual words, use $ instead of \\b (i.e. end of string):

(?=(?:rk|bhk)$)

Here is my IDEONE demo

Upvotes: 0

SamWhan
SamWhan

Reputation: 8332

This should do the trick:

(.*)(bhk|rk)

First capture holds the "number" part, and the second bhk OR rk.

Regards

Upvotes: 1

Codebender
Codebender

Reputation: 14438

You can use the following regex "(?=bhk|rk)" with split.

str.split("(?=bhk|rk)");

This will split it if there is one of bhk or rk.

Upvotes: 2

AnkeyNigam
AnkeyNigam

Reputation: 2820

String string = "2pbhk";
String first_part, second_part = null;
if(string.contains("bhk")){
first_part = string.substring(0, string.indexOf("bhk"));
second_part = "bhk";
}
else if(string.contains("rk")){
first_part = string.substring(0, string.indexOf("rk"));
second_part = "rk";
}

Try the above once, not using regex but should work.

Upvotes: 0

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