CODEWITHSUNDEEP
iosswiftnspredicatensrange
SlopTonio
SlopTonio

Reputation: 1105

Error: Int is not convertible to NSRange

I'm getting the error:

int is not convertible to NSRange

on var range:NSrange = 0:

   let predicate = NSPredicate(block: { (city: AnyObject!, b: [NSObject : AnyObject]!) -> Bool in
            var range:NSRange = 0;  //convert error happens here on 0
            if city is NSString {
                range = city.rangeOfString(searchBarText, options: NSStringCompareOptions.CaseInsensitiveSearch)
            }

            return range.location != NSNotFound
        })

any ideas on how to fix this?

Upvotes: 0

Views: 594

Answers (2)

vadian
vadian

Reputation: 285079

NSRange is a struct with members location and length, not an Int

use the initializer

var range: NSRange = NSRange(location:0, length:0)

or the convenience function

var range: NSRange = NSMakeRange(0, 0)

Upvotes: 1

Code Different
Code Different

Reputation: 93161

Your init statement was wrong. NSRange is a struct with a location and a range value. Change that to:

var range = NSMakeRange(NSNotFound, 0)

Upvotes: 4

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