CODEWITHSUNDEEP
pythonregexpython-3.xreplace
RhymeGuy
RhymeGuy

Reputation: 2112

Python - how to remove specific words from list?

I have a list like:

 defaultdict(<class 'list'>, {'Web': ['site: www.domain.com'], 'Phone': ['(111) 222-333', '(222) 333-444'], 'VAT': ['987654321'], 'Fax': ['(444) 555-666', '(777) 888-999'], 'E-mail': ['adress: [email protected]', 'address: [email protected]'], 'ID': ['number:1234567890']})

I want to clean words like: site:, adress: number:.

Output should be:

 defaultdict(<class 'list'>, {'Web': ['www.domain.com'], 'Phone': ['(111) 222-333', '(222) 333-444'], 'VAT': ['987654321'], 'Fax': ['(444) 555-666', '(777) 888-999'], 'E-mail': ['[email protected]', '[email protected]'], 'ID': ['1234567890']})

I know that I can remove words from specific list item like:

for em in d["E-mail"]:
    print(em.replace("address: ","",1))

but I'm looking for something that would clean whole list.

Upvotes: 2

Views: 479

Answers (3)

SmartElectron
SmartElectron

Reputation: 1441

Similar to Padraic Cunningham response but with regex:

In [39]: import re

In [40]: s = re.compile('[a-zA-Z]+:\s?')

In [41]: d={'Web': ['site: www.domain.com'], 'Phone': ['(111) 222-333', '(222) 333-444'], 'VAT': ['987654321'], 'Fax': ['(444) 555-666', '(777) 888-999'], 'E-mail': ['adress: [email protected]', 'address: [email protected]'], 'ID': ['number:1234567890']}

In [42]: def clean(dict_):
   ....:     for k, v in dict_.items():
   ....:         dict_[k] = map(lambda x: s.sub('', x), v)
   ....:

In [43]: clean(d)
Out[43]:
{'E-mail': ['[email protected]', '[email protected]'],
 'Fax': ['(444) 555-666', '(777) 888-999'],
 'ID': ['1234567890'],
 'Phone': ['(111) 222-333', '(222) 333-444'],
 'VAT': ['987654321'],
 'Web': ['www.domain.com']}

Upvotes: 0

Padraic Cunningham
Padraic Cunningham

Reputation: 180391

You just want the substring after the :, so either splitting will get us the substring or nothing will be removed if there is no : in the string:

for k,v in d.items():
    d[k] = [s.split(":", 1)[-1].lstrip() for s in v ]

print(d)

Output:

{'E-mail': ['[email protected]', '[email protected]'], 'Phone': ['(111) 222-333', '(222) 333-444'], 'ID': ['1234567890'], 'Web': ['www.domain.com'], 'VAT': ['987654321'], 'Fax': ['(444) 555-666', '(777) 888-999']}

Using [-1] as the index will mean we either get the second of two or the only string if there is nothing split. We also need to lstrip any leading whitespace from the substring after splitting.

You could also apply the same logic as you add the data to your defaultdict to avoid having to iterate over and mutate the dict values after they have already been assigned.

Upvotes: 4

JVamcas
JVamcas

Reputation: 132

for em in dict:

   if ":" in dict[em]
   a=dict[em].split(":")
   a.remove(a[0])
   print(a)

Try this code here

Upvotes: 0

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