Reputation: 6023
I am generating a Django model based on an abstract model class AbstractAttr
and a normal model (let's say Foo
).
I want my foo/models.py
to look like this:
from bar.models import Attrs
# ...
class Foo(models.Model):
....
attrs = Attrs()
In the Attrs class which mimics a field I have a contribute_to_class
that generates the required model using type()
. The generated model c is called FooAttr.
Everything works. If I migrate, I see FooAttr appear in the proper table.
EXCEPT FOR ONE THING.
I want to be able to from foo.models import FooAttr
. Somehow my generated FooAttr class is not bound to the models.py file in which it is generated.
If I change my models.py to this:
class Foo(models.Model):
# ...
FooAttr = generate_foo_attr_class(...)
it works, but this is not what I want (for example, this forces the dev to guess the generate class name).
Is what I want possible, define the class somewhat like in the first example AND bind it to the specific models.py module?
The project (pre-Alpha) is here (in develop branch): https://github.com/zostera/django-mav
Some relevant code:
def create_model_attribute_class(model_class, class_name=None, related_name=None, meta=None):
"""
Generate a value class (derived from AbstractModelAttribute) for a given model class
:param model_class: The model to create a AbstractModelAttribute class for
:param class_name: The name of the AbstractModelAttribute class to generate
:param related_name: The related name
:return: A model derives from AbstractModelAttribute with an object pointing to model_class
"""
if model_class._meta.abstract:
# This can't be done, because `object = ForeignKey(model_class)` would fail.
raise TypeError("Can't create attrs for abstract class {0}".format(model_class.__name__))
# Define inner Meta class
if not meta:
meta = {}
meta['app_label'] = model_class._meta.app_label
meta['db_tablespace'] = model_class._meta.db_tablespace
meta['managed'] = model_class._meta.managed
meta['unique_together'] = list(meta.get('unique_together', [])) + [('attribute', 'object')]
meta.setdefault('db_table', '{0}_attr'.format(model_class._meta.db_table))
# The name of the class to generate
if class_name is None:
value_class_name = '{name}Attr'.format(name=model_class.__name__)
else:
value_class_name = class_name
# The related name to set
if related_name is None:
model_class_related_name = 'attrs'
else:
model_class_related_name = related_name
# Make a type for our class
value_class = type(
str(value_class_name),
(AbstractModelAttribute,),
dict(
# Set to same module as model_class
__module__=model_class.__module__,
# Add a foreign key to model_class
object=models.ForeignKey(
model_class,
related_name=model_class_related_name
),
# Add Meta class
Meta=type(
str('Meta'),
(object,),
meta
),
))
return value_class
class Attrs(object):
def contribute_to_class(self, cls, name):
# Called from django.db.models.base.ModelBase.__new__
mav_class = create_model_attribute_class(model_class=cls, related_name=name)
cls.ModelAttributeClass = mav_class
Upvotes: 2
Views: 167
Reputation: 6023
Thanks all for thinking about this. I have updated the source code of the project at GitHub and added more tests. See https://github.com/zostera/django-mav
Since the actual generation of the models is done outside of foo/models.py
(it takes place in mav/models.py
, it seems Pythonically impossible to link the model to foo/models.py
. Also, after rethinking this, it seems to automagically for Python (explicit is better, no magic).
So my new strategy is to use simple functions, a decorator to make it easy to add mav
, and link the generated models to mac/attrs.py
, so I can universally from mav.attrs import FooAttr
. I also link the generated class to the Foo
model as Foo._mav_class.
(In this comment, Foo
is of course used as an example model that we want to add model-attribute-value to).
Upvotes: 0
Reputation: 2015
I see you create the model from within models.py, so I think you should be able to add it to the module's globals. How about this:
new_class = create_model_attribute_class(**kwargs)
globals()[new_class.__name__] = new_class
del new_class # no need to keep original around
Upvotes: 1