CODEWITHSUNDEEP
.netregexpowershell
Luis Lavieri
Luis Lavieri

Reputation: 4129

Regex patterns in Powershell

I am trying to retrieve the guids of projects within a .sln file using regular expressions

So, for instance, if I have in the file a project like this:

Project("{FAE04EC0-301F-11D3-BF4B-00C04F79EFBC}") = "SomeProject", "SomeProject\SomeProject.csproj", "{F5EF941A-49AD-404D-9EB1-209A75D4113F}"
EndProject

I would do something like this in my script:

$projectsInSolution = Select-String "$file" -pattern 'Project' 
$lineProjectsInFile = $projectsInSolution -match " `"{\S*}"

In the regular expression, I leave the whitespace because the real guid is F5EF941A-49AD-404D-9EB1-209A75D4113F

However, when I run this, I get

C:\...\...\...\....sln:6:Project("{FAE04EC0-301F-11D3-BF4B-00C04F79EFBC}") = "SomeProject", "SomeProject\SomeProject.csproj", "{F5EF941A-49AD-404D-9EB1-209A75D4113F}"

Why I am not getting the guid only?

I tested it in regexr.com and it seems so be working

Thank you

Edit

This is what I am doing now. But, not getting anything

$projectsInSolution = Select-String "$solutionFileStr" -pattern 'Project' 
$lineProjectsInFile = $projectsInSolution -match "(?<={)[^}]+(?=}`"\s*EndProject)"

ForEach($line in $lineProjectsInFile)
{
    Write-Output "$line"
}

Upvotes: 1

Views: 218

Answers (3)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 627537

You may use the following regex:

{(?<GUID>[^}]+)}[^{}]*$

See demo

Then you need to access it the following ways:

$projectsInSolution = Select-String "$solutionFileStr" -pattern '^Project' 
$guids = $projectsInSolution.line -match "({(?<GUID>[^}]+)}[^{}]*$"

Perhaps, this will be enough:

select-string -path <file_path> -pattern '({(?<GUID>[^}]+)}[^{}]*$' -allmatches  |
  foreach-object {$_.matches} |
   foreach-object {$_.groups[1].value} |
    Select-Object -Unique

Upvotes: 0

Mathias R. Jessen
Mathias R. Jessen

Reputation: 175085

You could use a capture group:

$Pattern = '\{(?<RealGuid>[0-9A-F]{8}([0-9A-F]{4}){3}[0-9A-F]{12})\}"$'
$RealGuid = Get-Content -Path $file | ForEach-Object {
    if($_ -match $Pattern){
        $Matches['RealGuid']
    }
}

Upvotes: 0

TheMadTechnician
TheMadTechnician

Reputation: 36342

I think your issue isn't with your RegEx but with how you're running it. Your Select-String command outputs a Microsoft.PowerShell.Commands.MatchInfo object, so what you're going to want to match against for that is the Line property. Also, if all you want is the GUID, I would use -Replace, and make the GUID a capture group, and replace the entire line with just the capture group. Something like this:

$file = 'c:\temp\test.txt'
$projectsInSolution = Select-String "$file" -pattern '^Project'
$lineProjectsInFile = $projectsInSolution.line -replace "^.+ `"{(\S*)}.*$", '$1'

That will result in $lineProjectsInFile containing an array of strings that are just the project GUIDs.

Upvotes: 3

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