CODEWITHSUNDEEP
wxpythonopenfiledialog
jmcampbell
jmcampbell

Reputation: 388

wx.FileDialog doesn't set directory

I am trying to open a file dialog to a directory other than the one in which I am working. I tried this:

dlg = wx.FileDialog(self, "Open", style=wx.FD_OPEN)
dlg.SetDirectory("C:\Users\tech\Desktop\Circuit Design Tool\Program Files")
dlg.ShowModal()
file_name = dlg.GetPath()
dlg.Destroy()

and this:

directory = "C:\Users\tech\Desktop\Circuit Design Tool\Program Files"
dlg = wx.FileDialog(self, "Open", directory, style=wx.FD_OPEN)
dlg.ShowModal()
file_name = dlg.GetPath()
dlg.Destroy()

but they both open to the directory in which I am working. Does anyone know what I'm doing wrong?

Upvotes: 0

Views: 2244

Answers (3)

Jan
Jan

Reputation: 952

Late to the party, but since it might help others with the same problem:

As nepix32 correctly explained, the backslashes need to be escaped. I found that this is still insufficent to get it working, but it started to work once I included an additional trailing backslash, so both this:

dlg = wx.FileDialog(self, "Open", style=wx.FD_OPEN)
dlg.SetDirectory("C:\\Users\\long\\path\\to\\Program Files\\")

and this:

directory = "C:\\Users\\long\\path\\to\\Program Files\\"
dlg = wx.FileDialog(self, "Open", directory, style=wx.FD_OPEN)

work for me (note the trailing \\ at the end of the path).

If you use this, a raw string isn't sufficient to disambiguate a last backslash from a literal quote sign, so you have to escape the backslashes instead. Or use forward slashes.

Upvotes: 0

Werner
Werner

Reputation: 2096

The following works for me:

dataDir = r"C:\Users\tech\Desktop\Circuit Design Tool\Program Files"

with wx.FileDialog(None, 'Open', dataDir,
                  style=wx.FD_OPEN | wx.FD_FILE_MUST_EXIST) as dlg:
            if dlg.ShowModal() == wx.ID_OK:
                dbfilename = dlg.GetPath()
                dataDir, dbFile = os.path.split(dbfilename)

Don't know why SetDirectory does not work, but in the other one you are not giving a default dir, see: http://wxpython.org/Phoenix/docs/html/FileDialog.html?highlight=filedialog#api-class-api

Upvotes: 0

nepix32
nepix32

Reputation: 3062

This has nothing to do with wxPython:

Try using this path with e. g. open(...) and it will also not work.

Reason: Som backslash/byte combinations will result in interpretation as string literals, e. g. "\t" as tab character. To avoid this, you can declare the string as "raw" with the r prefix, like this:

"\t" == r"\t"

Of course, if you are on windows and the path contains unicode characters, it will get interesting again :)

Upvotes: 1

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