CODEWITHSUNDEEP
phpexec
Udayaditya Barua
Udayaditya Barua

Reputation: 1162

ls -ltr using PHP exec()

as the problem states.. when i do 

exec("ls -ltr  > output.txt 2>&1",$result,$status);

its different from the normal output. An extra column gets added. something like

-rw-r--r-- 1 apache   apache    211 Jul  1 15:52 withoutsudo.txt
-rw-r--r-- 1 apache   apache      0 Jul  1 15:53 withsudo.txt

where as when executed from the command prompt its like 

-rw-r--r-- 1 apache   apache    211 2010-07-01 15:52 withoutsudo.txt
-rw-r--r-- 1 apache   apache    274 2010-07-01 15:53 withsudo.txt
-rw-r--r-- 1 apache   apache    346 2010-07-01 15:55 sudominusu.txt
-rw-r--r-- 1 apache   apache    414 2010-07-01 15:58 sudominusu.txt

See the difference. So in the first output , my usual awk '{print $8}' fails. I was facing the same problem with cron. But solved it by calling 

./$HOME/.bashrc

in the script. But not happening using php. If somehow i can "tell" php to "exec" from the usual environment. Any help would be appreciated.

Upvotes: 0

Views: 1735

Answers (4)

D.Shawley
D.Shawley

Reputation: 59583

The output of ls is heavily dependent on the environment (e.g., LANG being the important variable here). Why not use a combination of scandir, stat, and krsort?

function ls($dir_name) {
  $finfo = array();
  foreach (scandir($dir_name) as $file_name) {
    $s = stat(join('/', array($dir_name,$file_name)));
    $finfo[$file_name] = $s['mtime'];
  }
  krsort($finfo);
  return array_keys($finfo);
}

This will be safer and a lot more efficient than shelling out to ls. Not to mention that you get the benefit of being about to customize the sorting and filter the results in ways that are difficult to do inside of an exec.

BTW: I am by no means a PHP expert, so the above snippet is likely to be incredibly unsafe and full of errors.

Upvotes: 0

towe75
towe75

Reputation: 1470

I guess you are only interested in the file names and you want to sort with reverse time. Try this:

ls -tr1 > output.txt 2>&1

You'll get a list with only the file names, so you don't need awk at all.

Another solution is to specify the time format with "--time-style iso". Have a look at the man page

Upvotes: 1

Sjoerd
Sjoerd

Reputation: 75629

In your login shell, ls is probably aliased so that it prints another date. This would be in your .basrc or .bash_profile.

Explicitly pass the --time-style= option to ls to ensure that it prints the date in the expected format when using PHP.

Upvotes: 2

Piskvor left the building
Piskvor left the building

Reputation: 92772

That's not an extra output, that's a difference in formatting the date. Apparently you have a different locale set in PHP and in bash ("command prompt").

(in bash, running export LANG=C or export LANG=en_US gives the result with three-letter month name)

Upvotes: 1

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