Reputation: 151
I am truly sorry that I could not provide details for the exact equation that I am working with. It is a very complicated second-order differential equation in the form similar to this:
where function
a(z) ~ e(z) and g(z)
are given. p
is constant.
I also have the boundary conditions.
Is it possible to solve f(z)
with the help of matlab?
Any suggestion would be greatly appreciated. Thanks a lot.
Here is how I defined my function. a1 ~ g1
and fna ~ fng
are defined and stored in Gdata.mat
:
function xp=myfunc(t,p)
% x = [d2f df f df2 f2 d2f2]
% xp = [df d2f f2 df2 d3f d2f2]
load GData
xp=zeros(6,1); % [f df d2f f2 df2]
% f
fprintf('%d\n',length(xp));
fprintf('%d\n',length(p));
xp(1) = x(2); % df
xp(2) = x(1); % d2f
% f2
xp(4) = x(4); % df2
xp(6) = x(6); % d2f2
xp(5) = (...
b1(t)*p(3) + b(t)*p(2) + ...
c1(t)*p(3)^3 + 3*fnc(t)*p(3)^2*p(2) + ...
d1(t)*p(3)^5 + 5*fnd(t)*p(3)^4*p(2) + ...
e1(t)*p(3)^7 + 7*fne(t)*x(3)^6*p(2) - ...
f1(t)*p(2)*p(3) + f1(t)*p(1)*p(3) + f1(t)*p(2)^2 - ...
g1(t)*p(4) - fng(t)*p(6) + ...
q*p(2) - a1(t)*p(1)...
) * 1/(fna(t));
then I called:
[TEMP,POL] = ode45('odesolver',[0,1],[0,0,0,0,0,0]);
function dp=odesolver(t,p)
% dp = [df d2f d3f]
syms x;
load BData;
load GData;
dp=zeros(3,1); % [f df d2f]
A = interp1(t_data,At,t);
B = interp1(t_data,Bt,t);
C = interp1(t_data,Ct,t);
D = interp1(t_data,Dt,t);
E = interp1(t_data,Et,t);
F = interp1(t_data,Ft,t);
G = interp1(t_data,Gt,t);
A1 = interp1(t_data,A1t,t);
B1 = interp1(t_data,B1t,t);
C1 = interp1(t_data,C1t,t);
D1 = interp1(t_data,D1t,t);
E1 = interp1(t_data,E1t,t);
F1 = interp1(t_data,F1t,t);
G1 = interp1(t_data,G1t,t);
dp(1) = p(2); % f'
dp(2) = p(3); % f''
dp(3) = (...
B1*p(3) + B*p(2) + ...
C1*p(3)^3 + 3*C*p(3)^2*p(2) + ...
D1*p(3)^5 + 5*D*p(3)^4*p(2) + ...
E1*p(3)^7 + 7*E*p(3)^6*p(2) - ...
F1*p(2)*p(3) + F*p(1)*p(3) + F*p(2)^2 - ...
2*G1*p(2)*p(1) + 2*G*p(3)*p(1) + 2*G*p(2)*p(2) + ...
q*p(2) - A1*p(1)) * 1/(A);
Upvotes: 0
Views: 669
Reputation: 13886
Answer based on the discussion and edited question:
There are several obstacles in using ode45
to solve your differential equation, but none of them are a showstopper:
ode45
, as in this question.ode
function to allow solving with ode45
t
using your time-dependent data to get the corresponding values of your variables, as in this other question.So your code should look something like this (I have assumed that you have a common time vector for all your time-dependent data in your GData
file, this may not be the case, you may have a different time vector for each variable - adjust the code if necessary; either way make sure your time-dependent data is defined on the time interval on which your are calling ode45
):
function dx=myfunc(t,x)
% x = [d2f df f df2 f2 d2f2]
% dx = [d3f d2f df d2f2 df2 d3f2]
load GData % I assume this contains b1, b, c1, etc... *and* the corresponding time vector, say t_data
dx=zeros(6,1); % [d3f d2f df d2f2 df2 d3f2]
fprintf('%d\n',length(dx));
fprintf('%d\n',length(x));
dx(1) = x(2); % double-check!!
dx(2) = x(1); % double-check!!
% double-check!!
dx(4) = x(4); % double-check!!
dx(6) = x(6); % double-check!!
B1 = interp1(t_data,b1,t);
B = interp1(t_data,b,t);
C1 = interp1(t_data,c1,t);
% etc... for the other variables
dx(5) = (...
B1*p(3) + B*p(2) + ...
C1*p(3)^3 + 3*FNC*p(3)^2*p(2) + ...
D1*p(3)^5 + 5*FND*p(3)^4*p(2) + ...
E1*p(3)^7 + 7*FNE*x(3)^6*p(2) - ...
F1*p(2)*p(3) + F1*p(1)*p(3) + F1*p(2)^2 - ...
G1*p(4) - FNG*p(6) + ...
q*p(2) - A1*p(1)...
) * 1/(FNA); % double-check!!
Upvotes: 0