Reputation: 11
I would like to know how to create a border in Pygame to stop the user controlled object from exiting the screen. Right now, I only have it so python prints some text when the user controlled object has come near one of the 4 sides.
Here is my code so far.
import pygame
from pygame.locals import *
pygame.init()
#Display Stuff
screenx = 1000
screeny = 900
screen = pygame.display.set_mode((screenx,screeny))
pygame.display.set_caption('Block Runner')
clock = pygame.time.Clock()
image = pygame.image.load('square.png')
#Color Stuff
red = (255,0,0)
green = (0,255,0)
blue = (0,0,255)
white = (255,255,255)
black = (0,0,0)
#Variables
x_blocky = 50
y_blocky = 750
blocky_y_move = 0
blocky_x_move = 0
#Animations
def Blocky(x_blocky, y_blocky, image):
screen.blit(image,(x_blocky,y_blocky))
#Game Loop
game_over = False
while not game_over:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
quit()
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_UP:
blocky_y_move = -3
if event.type == pygame.KEYUP:
if event.key == pygame.K_UP:
blocky_y_move = 0
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_DOWN:
blocky_y_move = 3
if event.type == pygame.KEYUP:
if event.key == pygame.K_DOWN:
blocky_y_move = 0
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_RIGHT:
blocky_x_move = 3
if event.type == pygame.KEYUP:
if event.key == pygame.K_RIGHT:
blocky_x_move = 0
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
blocky_x_move = -3
if event.type == pygame.KEYUP:
if event.key == pygame.K_LEFT:
blocky_x_move = 0
if x_blocky > 870 or x_blocky < 0:
print(' X Border')
if y_blocky > 750 or y_blocky < 2:
print(' Y Border')
y_blocky += blocky_y_move
x_blocky += blocky_x_move
screen.fill(white)
Blocky(x_blocky, y_blocky, image)
pygame.display.update()
clock.tick(60)
Upvotes: 1
Views: 15565
Reputation: 27557
You can set the boundaries using the min
and max
functions.
Here is the concept:
We have a pygame object that moves in all four directions; lets say the user holds down the LEFT arrow key, so that the object reaches the top of the screen. The y-coordinate of the top of the screen will always be 0
, so we want the object to come to a stop at y-coordinate 0
.
This may seem as simple as:
if char.rect.y > 0:
char.rect.y -= char.speed
But this will result in a bug ig char.speed
is greater than 1
. Like when the object is at y-coordinate 5
,
and its speed is 10
; the condition still allows for one more step for the object, resulting in the object
coming 5
pixels out of the pygame window. What we want to do is more like:
if char.rect.y > 0:
char.rect.y -= char.speed
if char.rect.y < 0:
char.rect.y = 0
to push the object back into the boundaries. The above block of code can be simplified with the max
function:
self.rect.y = max([self.rect.y - self.speed, 0])
For the object moving down:
if char.rect.y < HEIGHT - char.height:
char.rect.y += char.speed
if char.rect.y > HEIGHT - char.height:
char.rect.y = HEIGHT - char.height
or, the more efficient and clean method:
self.rect.y = min([self.rect.y + self.speed, HEIGHT - self.height])
For going left and right, simply replace the y
s and height
(and HEIGHT
) from two lines above with x
s and widths
(and WIDTH
).
All together:
import pygame
pygame.init()
WIDTH = 600
HEIGHT = 600
wn = pygame.display.set_mode((WIDTH, HEIGHT))
class Player:
def __init__(self):
self.speed = 1
self.width = 20
self.height = 20
self.color = (255, 255, 0)
self.rect = pygame.Rect((WIDTH - self.width) / 2, (HEIGHT - self.height) / 2, 20, 20)
def up(self):
self.rect.y = max([self.rect.y - self.speed, 0])
def down(self):
self.rect.y = min([self.rect.y + self.speed, HEIGHT - self.height])
def left(self):
self.rect.x = max([self.rect.x - self.speed, 0])
def right(self):
self.rect.x = min([self.rect.x + self.speed, WIDTH - self.width])
def draw(self):
pygame.draw.rect(wn, self.color, self.rect)
char = Player()
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
keys = pygame.key.get_pressed()
if keys[pygame.K_UP]:
char.up()
if keys[pygame.K_DOWN]:
char.down()
if keys[pygame.K_LEFT]:
char.left()
if keys[pygame.K_RIGHT]:
char.right()
wn.fill((0, 0, 0))
char.draw()
pygame.display.update()
Good luck!
Upvotes: 0
Reputation: 47
Also, you have some redundant code with your keyboard movement. Instead of writing
if event.type == KEYDOWN:
over and over again, group the KEYUP if statements and KEYDOWN if statements.
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_UP:
blocky_y_move = -3
elif event.key == pygame.K_DOWN:
blocky_y_move = +3
etc, and:
if event.type == pygame.KEYUP:
if event.key == pygame.K_UP:
blocky_y_move = 0
elif event.type == pygame.K_DOWN:
blocky_y_move = 0
etc
Upvotes: 0
Reputation: 101052
Don't use integers to store your position. Use a Rect
.
So instead of
x_blocky = 50
y_blocky = 750
use
blocky_pos = pygame.rect.Rect(50, 750)
Now you can simply use
blocky_pos.move_ip(blocky_x_move, blocky_y_move)
to move your object.
After moving, you can simply call clamp
/clamp_ip
to ensure the blocky_pos
Rect
is always inside the screen.
blocky_pos.clamp_ip(screen.get_rect())
Also, you don't need to define basic colors yourself, you could simply use pygame.color.Color('Red')
for example.
I also suggest you use pygame.key.get_pressed()
to get all pressed keys to see how to move your object instead of creating 1000 lines of event handling code.
Upvotes: 3
Reputation: 6059
Well, simply don't increase your move variable any further, if you detect that the user object is near or at the border. Or reverse the move direction, depending on your general intent.
if x_blocky > 870 or x_blocky < 0:
print(' X Border')
blocky_x_move = 0
if y_blocky > 750 or y_blocky < 2:
print(' Y Border')
blocky_y_move = 0
Upvotes: 1