CODEWITHSUNDEEP
codeigniterviewnested
Vito
Vito

Reputation: 776

How to pass data from a view to another

I have the following problem:

I have a controller in which I have:

$this->load->model('girl_model');
$ragazze = $this->girl_model->get_girls();
$data['content'] = 'view_news';
$data['girls'] = $girls;

in my main view I have:

<html>
<head>
    <title> </title>
<link rel="stylesheet" type="text/css"  href="/assets/css/style.css">
</head>
<body>
    <div id="menu">
        <li><a href="#">Home</a></li>
        <li><a href="#">About</a></li>
        <li><a href="#">Contact</a></li>
    </div>

    <div id="main-content">
        <?php $this->load->view($content,  array('girls' => $girls) ); ?>

    </div>

    <div id="footer">
        Copy Right 2015 
    </div>
</body>

In my subview I have:

<?php echo $girls ?>    
<?php foreach ($girls as $girl):?>
        <tr>
            <td><?php echo $girl; ?></td><br/>
        </tr>
<?php endforeach;?>

The problem is that I don't see the results of my query in the subview. I only see the Array word printed. It's like something is not passed correctly. I'm new in CodeIgniter and I don't understand why it doesn't work. Can you properly explain to me the solution?

Upvotes: 0

Views: 3090

Answers (2)

David Coder
David Coder

Reputation: 1138

HI your code should be :

controller :

$this->load->model('girl_model');
$ragazze = $this->girl_model->get_girls();
$data['content'] = 'view_news';
$data['girls'] = $ragazze ;
//echo '<pre>';print_r($data) //debug here if you want
this->load->view('YourMainView',$data);

Main View :

<html>
<head>
    <title> </title>
<link rel="stylesheet" type="text/css"  href="/assets/css/style.css">
</head>
<body>
    <div id="menu">
        <li><a href="#">Home</a></li>
        <li><a href="#">About</a></li>
        <li><a href="#">Contact</a></li>
    </div>

    <div id="main-content">
        <?php $this->load->view($content,$girls); ?>

    </div>

    <div id="footer">
        Copy Right 2015 
    </div>
</body>

In Sub View :

<?php print_r($girls); ?>// $girls is an array you can not echo it you have to use print_r().
<?php foreach ($girls as $girl) ?>
        <tr>
            <td><?php echo $girl['field_name']; ?></td>//field name in your table.
        </tr>
<?php endforeach;?>

Upvotes: 1

shankar kumar
shankar kumar

Reputation: 648

just load that $data in first view and it will that variable is automatically available in included view. in your case. please change according to written bellow.

 $this->load->model('girl_model');
 $ragazze = $this->girl_model->get_girls();
 $data['content'] = 'view_news';
 $data['girls'] = $ragazze;

load this data in this controller.

     $this->load->view('viewfilename',$data);

Now $girls is available for viewfilename.php and any view included in this viewfilename.php .

      <html>
      <head>
      <title> </title>
      <link rel="stylesheet" type="text/css"  href="/assets/css/style.css">
     </head>
     <body>
      <div id="menu">
    <li><a href="#">Home</a></li>
    <li><a href="#">About</a></li>
    <li><a href="#">Contact</a></li>
       </div>

<div id="main-content">
    <?php $this->load->view($content); ?>

</div>

<div id="footer">
    Copy Right 2015 
</div>

now change it according to it and $girls will be available to $content views as well.

Upvotes: 1

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