Reputation: 91
The code that we already have return us JsonObject
. What I want to do is to add a new key and the value for it.
For example, we have an object like this:
{"id":"12","name":"test"}
I want to transform it into this:
{"id":"12","name":"test","status":"complete"}
I didn't find what I need in documentation except using put method. So I wrote this code:
JsonObject object = getJsonObject();
JsonString val = new JsonString() {
public JsonValue.ValueType getValueType() {
return JsonValue.ValueType.STRING;
}
public String getString() {
return "complete";
}
public CharSequence getChars() {
return (CharSequence) "complete";
}
};
object.put("status", val);
But it doesn't work, crashing with :
java.lang.UnsupportedOperationException
I can't understand what is wrong. Have I any other option to complete such a task?
Upvotes: 1
Views: 3227
Reputation: 916
Not sure if object.put works but you can use the following way to append the details to JSON value:
You can create a different JSON object with the key and value that you want to add to the JSON object and the user object.merge(status, complete, String::concat);
merge() checks for the key:'status' in your JSON object if it does'nt find it then it adds that key:value pair or else it replaces it
.You are not able to compile it because you may not be using jre 1.8.
I've Just verified the following method:
Just create a new JSONObject(org.json.JSONObject
not javax.json.JsonObject
)
JSONObject modifiedJsonObject= new JSONObject(object.toString());
modifiedJsonObject.put("status", "complete");
Upvotes: 0
Reputation: 7772
I don't think JsonObject
instances are meant to be modified.
I think your best option is to create a new object, copy the existing properties and add the new property to it.
You can use https://docs.oracle.com/javaee/7/api/javax/json/JsonObjectBuilder.html
Upvotes: 1