Reputation: 6870
I am looking for a way to avoid creating duplicates in my digraph (I use the jgrapht library).
I read some topics which said to use: directedGraph.setCloneable(false);
But it doesn't seem to be right, can't find it in the library's documentation and I get an error on this line saying it doesn't exists.
I created my graph using:
public static DirectedGraph<Point, DefaultEdge> directedGraph = new DefaultDirectedGraph<Point, DefaultEdge>(DefaultEdge.class);
And then it adds vertices to it based on the flood fill algorithm (adds vertices and edges as the algorithm go through every point, below is a part of it):
// Up
xToFillNext = x-1;
yToFillNext = y;
if (xToFillNext==targetX && yToFillNext==targetY && !forbiddenDirection.equals(Direction.UP)) {
Point myPoint = new Point(x, y);
Point myNextPoint = new Point(xToFillNext, yToFillNext);
directedGraph.addVertex(myPoint);
directedGraph.addVertex(myNextPoint);
directedGraph.addEdge(myPoint, myNextPoint);
return true;
} else if (xToFillNext>=0 && originValue==matrix[xToFillNext][yToFillNext] && !forbiddenDirection.equals(Direction.UP)) {
Point myPoint = new Point(x, y);
Point myNextPoint = new Point(xToFillNext, yToFillNext);
directedGraph.addVertex(myPoint);
directedGraph.addVertex(myNextPoint);
directedGraph.addEdge(myPoint, myNextPoint);
fillingReachedTargetPosition =
fillReachesTargetPosition(matrix, xToFillNext, yToFillNext, targetX, targetY, fillValue, Direction.DOWN );
if (fillingReachedTargetPosition) {
return true;
}
}
But when I print the list of vertices, there are duplicates which I either need to get rid of, or avoid them to be created. Is there a way to do it ?
EDIT: I created a Point class:
public static class Point {
public int x;
public int y;
public Point(int x, int y)
{
this.x = x;
this.y = y;
}
@Override
public String toString() {
return ("[x="+x+" y="+y+"]");
}
}
Upvotes: 4
Views: 1332
Reputation: 1915
In order to detect duplicate vertices you need to supply also method for equals
and hashCode
. Ohterwise JVM does not know, how to compare the objects, and uses object id (==
) which would not identify two different object of class Point as duplicate or equal.
e.g. ( The hashCode has countless number of possible implementations)
@Override
public int hashCode() {
int hash = 7;
hash = 71 * hash + this.x;
hash = 71 * hash + this.y;
return hash;
}
@Override
public boolean equals(Object other)
{
if (this == other)
return true;
if (!(other instanceof Point))
return false;
Point otherPoint = (Point) other;
return otherPoint.x == x && otherPoint.y == y;
}
Upvotes: 2
Reputation: 20125
I tried creating some duplicate vertices and edges with the following program:
import org.jgrapht.DirectedGraph;
import org.jgrapht.graph.DefaultDirectedGraph;
import org.jgrapht.graph.DefaultEdge;
import java.awt.Point;
public class JgraphtTest {
public static void main(String[] args) {
DirectedGraph<Point, DefaultEdge> directedGraph = new DefaultDirectedGraph<Point, DefaultEdge>(DefaultEdge.class);
Point zero = new Point(0, 0), zero2 = new Point(0, 0), one = new Point(1, 1), two = new Point(2, 2);
directedGraph.addVertex(zero);
directedGraph.addVertex(one);
directedGraph.addVertex(two);
directedGraph.addVertex(zero2); // should be a dup
directedGraph.addEdge(zero, one);
directedGraph.addEdge(one, two);
directedGraph.addEdge(zero2, one); // should be a dup
for (Point vertex : directedGraph.vertexSet()) {
System.out.format("vertex: %s\n", vertex);
}
for (DefaultEdge edge : directedGraph.edgeSet()) {
System.out.format("edge: %s\n", edge);
}
}
}
But it showed no duplicates in the output:
vertex: java.awt.Point[x=0,y=0]
vertex: java.awt.Point[x=1,y=1]
vertex: java.awt.Point[x=2,y=2]
edge: (java.awt.Point[x=0,y=0] : java.awt.Point[x=1,y=1])
edge: (java.awt.Point[x=1,y=1] : java.awt.Point[x=2,y=2])
So I'm guessing that you are using your own Point
class, but you're not properly overriding equals
and hashCode
. Without those methods being overridden, DirectedGraph
won't be able to tell if a vertex exists already or not.
Upvotes: 1