Reputation: 4367
I like to sum values in a table based on a condition taken from the same table called. The structure of the table as per below. The table is called Data
Data
Type Value
1 5
1 10
1 15
1 25
1 15
1 20
1 5
2 10
3 5
If the Value of Type 2 is larger than the Value of Type 3 then I like to subtract the Value of Type 2 from the sum of all the Values in the table. I'm not sure how to write the IF statements using Values looked up in the table. I have tried below but it doesn't work.
SELECT SUM(Value)-IF(SELECT Value FROM Data WHERE Type=2>SELECT Value
FROM Data WHERE Type=3 THEN SELECT Value FROM Data
WHERE Type=2 ELSE SELECT Value FROM Data WHERE Type=3) FROM Data
or
SELECT SUM(d.Value)-IIF(a.type2>b.type3, a.type2, b.type3)
FROM Data d, (SELECT Value AS type2 FROM Data WHERE Type=2) a,
(SELECT Value AS type3 FROM Data WHERE Type=3) b
Upvotes: 0
Views: 6432
Reputation: 4367
Thanks for pointing me in the right direction. This is what I came up with in the end. It is a little bit different to the reply above since I'm using MS Access
SELECT SUM(Value)-IIf(SUM(IIf(Type=2, Value, 0)>SUM(IIf(Type=3, Value, 0), SUM(IIf(Type=2, Value, 0), SUM(IIf(Type=3, Value, 0) FROM Data
It is them same as the second suggestion above but adapted to MS Access SQL.
Upvotes: 0
Reputation: 1269503
If I follow your logic correctly, then this would seem to do what you want:
select d.value - (case when d2.value > d3.value then d2.value else 0 end)
from data d cross join
(select value from data where type = 2) d2 cross join
(select value from data where type = 3) d3 ;
EDIT:
If you want just one number, then use conditional aggregation:
select sum(value) -
(case when sum(case when type = 2 then value else 0 end) >
sum(case when type = 3 then value else 0 end)
then sum(case when type = 2 then value else 0 end)
else 0
end)
from data;
Upvotes: 3