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arrayslinuxbash
Lidjan
Lidjan

Reputation: 154

Bash scripting & array pushing

I'm trying to make a script which will find a files, take their dirnames and then go there and do something. I have a problem with adding elements to array, who I want to be my dirnames container.

Code looks like this:

dirnames=()
while read -r line; do
        echo "Looking for dirname "$line
        dirname=$( dirname $(egrep -lir --include=pom.xml "<name>"$line"</name>" $application_dir))
        dirnames+=($dirname)
done < $modules_file

echo "Acquired dirnames"
echo $dirnames

And this is the answer:

Looking for dirname a
Looking for dirname b
Looking for dirname c
Acquired dirnames
/home/user/dev/workspace/a

I have only first dir in my "array". It looks like every another iteration is missing, and i know that these other dirnames are found because of i trying to swap lines.

I was reading a lot about arrays in bash, but everywhere this kind of approach works fine.

Any advice?

Upvotes: 1

Views: 564

Answers (2)

Drona
Drona

Reputation: 7234

I think the problem is with the way you are printing your dirnames array. ${dirnames} will only print the first element. Try printing it like this: 

echo ${dirnames[@]}

Upvotes: 0

paddy
paddy

Reputation: 63471

Bash syntax to expand the entire array is this:

echo ${dirnames[*]}

Or you can access individual elements. e.g.

echo ${dirnames[1]}

Or loop over array:

for d in ${dirnames[*]}; do
    echo $d
done

Upvotes: 1

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