CODEWITHSUNDEEP
jsonscala
user1735076
user1735076

Reputation: 3325

Converting files containing many JSON to List of maps in scala

Suppose I have a file:

JsonsFile.json

{"key1":"value11","key2":"value12","key3":"value13"}
{"key1":"value11","key2":"value12","key3":"value13"}
{"key1":"value11","key2":"value12","key3":"value13"}

It may have variable number of Jsons. How can I get List of Maps from this file? I would like to access elements like list(i)("key2")

Upvotes: 1

Views: 49

Answers (1)

John Sullivan
John Sullivan

Reputation: 1311

There are a number of scala libraries that process json, but I'm partial to json4s. this can easily parse json into scala, but the direct result isn't a map. If your json records posses a regular format (as your example suggests) then I would recommend something like this

import org.json4s._
import org.json4s.jackson.JsonMethods._
import scala.io.Source

case class Record(key1:String, key2:String, key3:String)
implicit val format = DefaultFormats

 val records = Source.fromFile("JsonFile.json").getLines.map(parse(_).extract[Record]).toList
 \\ records will be a List[Record], with elements accessible like
 records(1).key2

Upvotes: 1

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