Reputation: 406
following issue gets me a lack of understanding. I want to create a 1x1 transparent gif which will be provided by a servlet:
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setContentType("image/gif");
byte[] trackingGif = { 0x47, 0x49, 0x46, 0x38, 0x39, 0x61, 0x1, 0x0, 0x1, 0x0, (byte) 0x80, 0x0, 0x0,
(byte) 0xff, (byte) 0xff, (byte) 0xff, 0x0, 0x0, 0x0, 0x2c, 0x0, 0x0, 0x0, 0x0, 0x1, 0x0, 0x1, 0x0,
0x0, 0x2, 0x2, 0x44, 0x1, 0x0, 0x3b };
BufferedImage singlePixelImage = new BufferedImage(1, 1, BufferedImage.TYPE_4BYTE_ABGR);
Color transparent = new Color(0, 0, 0, 0);
singlePixelImage.setRGB(0, 0, transparent.getRGB());
response.setContentType("image/gif");
response.getOutputStream().write(trackingGif);
}
If i call the Servlet from Firefox, the Servlet is always called twice and Firebug tells me "The URL could not be loaded" and shows a broken Image.
Chrome for example does not call it twice.
Waht is wrong? is it really not a valid image?
Thanks in advance.
Upvotes: 2
Views: 1092
Reputation: 21902
The GIF data looks ok. But why recreate it if you already have the data?
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
byte[] trackingGif = { 0x47, 0x49, 0x46, 0x38, 0x39, 0x61, 0x1, 0x0, 0x1, 0x0, (byte) 0x80, 0x0, 0x0,
(byte) 0xff, (byte) 0xff, (byte) 0xff, 0x0, 0x0, 0x0, 0x2c, 0x0, 0x0, 0x0, 0x0, 0x1, 0x0, 0x1, 0x0,
0x0, 0x2, 0x2, 0x44, 0x1, 0x0, 0x3b };
response.setContentType("image/gif");
response.setContentLength(trackingGif.length);
OutputStream out = response.getOutputStream();
out.write(trackingGif);
out.close();
}
The calling the servlet twice I believe is a side effect of having Firefox + Firebug running. bug
Upvotes: 2