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xcodeswiftswift2xcode7
Omar Shiltawi
Omar Shiltawi

Reputation: 23

Cannot invoke 'split' with an argument list of type '(String, (String) -> Bool)' in SWIFT 2

The error: Cannot invoke 'split' with an argument list of type '(String, (String) -> Bool)'

Code i want to use: let nameArr = split(name) {$0 == "."}

Upvotes: 1

Views: 2301

Answers (1)

Victor Sigler
Victor Sigler

Reputation: 23459

Strings are No Longer Collections, String no longer conforms to CollectionType. You can use other alternatives like the function componentsSeparatedByString:

var name = "Victor.Hello.GYTT" 
let nameArr = name.componentsSeparatedByString(".") // [Victor, Hello, GYTT]

Another option is using the characters property:

let nameArr = split(name.characters) { $0 == "." }.map { String($0) }

With the new .init syntax in Xcode 7 beta 2, where init "can now be referenced like static methods" like in the following way:

let nameArr = split(name.characters) { $0 == "." }.map { String.init }

Or making the String conforms the protocol too, but Apple made a decision to remove String conformance to Sliceable, be carefull.

You can read more about notables changes in Changes to the Swift Standard Library in 2.0 beta 1 in the blog of @AirSpeedVelocity. Really nice.

I hope this help you.

Upvotes: 4

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