CODEWITHSUNDEEP
pythonbashfunction
dubbbdan
dubbbdan

Reputation: 2730

Pass variable to python function from bash script

I am really struggling trying to figure out to pass variables from a bash script to a python function I have made. I have looked over numberous posts about the same issue and cant seem to understand what I am missing.

I have a python function script named fname_function.py:

from glob import glob
import os
import sys

first_arg=sys.argv[1]
second_arg=sys.argv[2]
third_arg=sys.argv[3]

def gFpath(reach,drive,date):
    list1 = glob(os.path.normpath(os.path.join(drive, reach, date,'*')))
    list2 =[]
    for afolder in list1:
      list2.append(glob(os.path.normpath(os.path.join(drive, reach, date, afolder, 'x_y_class?.asc'))))
    return list2

if __name__=='__main__':
    gFpath(first_arg,second_arg,third_arg)

And my bash script looks like:

reach="R4a"
drive= "D:\\"
dte="2015_04"

fnames=$(python fname_function.py "$reach" "$drive" "$dte")

for fname in $fnames; do echo "Script returned $fname"; done

The variables are being passed to the python script, but I cant seem to get list2 back to my shell script.

Thanks,

Dubbbdan

Upvotes: 0

Views: 2264

Answers (1)

iobender
iobender

Reputation: 3486

You can just run the Python file directly, like python fname_function.py "$reach" "$drive" "$dte"

However, sys.argv[0] will be fname_function.py in this case, so you'll want to set first_arg to sys.argv[1] and increment the other numbers as well.

Also, you don't output anything in your Python script. You should make the end of your script read:

if __name__=='__main__':
    fnames = gFpath(first_arg,second_arg,third_arg)
    for fname in fnames:
        print(fname)

which will print out 1 result from gFpath on each line.

Upvotes: 3

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