packetie
packetie

Reputation: 5069

Define a map of map type in C++?

I am trying to define a unordered map from long to a map from long to FILE *, but keep getting compiler error. Any idea how to correct it?

#include <string>
#include <iostream>
#include <stdio.h>
#include<unordered_map>
using namespace std;

typedef unsigned long ulong;
typedef unsigned int uint;
typedef unsigned short uint16;
typedef unsigned char uchar;

typedef std::unordered_map<long, std::unordered_map<long, *FILE> > TYPE1;

int main(int argc, char *argv[]) {
    TYPE1 x;
    x[1][2] = fopen(argv[1], "rb");

    return 0;
}

Here is the compiler error

$ g++ -std=c++11 te2a.cc
te2a.cc:15:64: error: template argument 2 is invalid
te2a.cc:15:64: error: template argument 5 is invalid
te2a.cc:15:66: error: template argument 2 is invalid
te2a.cc:15:66: error: template argument 5 is invalid
te2a.cc:15:73: error: invalid type in declaration before ‘;’ token
te2a.cc: In function ‘int main(int, char**)’:
te2a.cc:19:5: error: invalid types ‘TYPE1 {aka int}[int]’ for array subscript

Upvotes: 0

Views: 103

Answers (2)

TryinHard
TryinHard

Reputation: 4118

Note the asterisk:

typedef std::unordered_map<long, std::unordered_map<long, *FILE>> TYPE1;

change it to:

typedef std::unordered_map<long, std::unordered_map<long, FILE*>> TYPE1;

Upvotes: 1

R2-Dequeue
R2-Dequeue

Reputation: 638

It's the placing of the asterisk:

typedef std::unordered_map<long, std::unordered_map<long, FILE*>> TYPE1;

will do it.

Upvotes: 4

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