Reputation: 1138
I am trying to deserialize some xml. Here it is:
<FooBars xmlns="http://foos">
<Id1 xmlns="http://bars">2</Id1>
<Id2 xmlns="http://bars">7</Id2>
<Info xmlns="http://bars">
<Data>
<Field1>text1</Field1>
<Field2>text2</Field2>
<Field3>text3</Field3>
</Data>
<Data>
<Field1>text5</Field1>
<Field2>text6</Field2>
<Field3>text7</Field3>
</Data>
</Info>
</FooBars>
I tried this:
var myData = (FooBars)serializer.Deserialize(foobars.CreateReader());
...
[XmlRoot(ElementName = "FooBars", Namespace = "http://foos")]
public class FooBars
{
[XmlElement(ElementName = "Id1", Namespace = "http://bars")]
public string Id1 { get; set; }
[XmlElement(ElementName = "Id2", Namespace = "http://bars")]
public string Id2 { get; set; }
[XmlElement(ElementName = "Info", Namespace = "http://bars")]
public List<Data> Info { get; set; }
}
public class Data
{
[XmlElement(ElementName = "Field1")]
public string Field1 { get; set; }
[XmlElement(ElementName = "Field2")]
public string Field2 { get; set; }
}
But it looks like the Data class is not considered part of the xml, since it is not able to read it. I am getting all the other elements (ids) but not the things defined in Data. Where am I wrong?
Upvotes: 0
Views: 103
Reputation: 787
via LinqPad - you can see the Field properties are null in the myData.Info
property, and that is your problem, right? UPDATED:
void Main()
{
string xmlString;
string path = @"C:\Temp\exampleXmlSO.xml";
using (StreamReader streamReader = File.OpenText(path))
{
xmlString = streamReader.ReadToEnd();
}
XmlSerializer serializer = new XmlSerializer(typeof(FooBars));
using (StringReader stringReader = new StringReader(xmlString))
{
var myData = (FooBars)serializer.Deserialize(stringReader);
Console.WriteLine(myData);
}
}
[XmlRoot(ElementName = "FooBars", Namespace = "http://foos")]
public class FooBars
{
[XmlElement(ElementName = "Id1", Namespace = "http://bars")]
public string Id1 { get; set; }
[XmlElement(ElementName = "Id2", Namespace = "http://bars")]
public string Id2 { get; set; }
[XmlArray(ElementName = "Info", Namespace = "http://bars"), XmlArrayItem("Data")] //<--
public List<Data> Info { get; set; }
}
[Serializable]
public class Data
{
[XmlElement(ElementName = "Field1")]
public string Field1 { get; set; }
[XmlElement(ElementName = "Field2")]
public string Field2 { get; set; }
[XmlIgnore]
public string Field3 { get; set; }
}
Upvotes: 0
Reputation: 15364
Presuming missing </Info>
tag is a typo, All you need is XmlArray
and XmlArrayItem
[XmlRoot(ElementName = "FooBars", Namespace = "http://foos")]
public class FooBars
{
[XmlElement(ElementName = "Id1", Namespace = "http://bars")]
public string Id1 { get; set; }
[XmlElement(ElementName = "Id2", Namespace = "http://bars")]
public string Id2 { get; set; }
[XmlArray(ElementName = "Info", Namespace = "http://bars"), XmlArrayItem("Data")] //<--
public List<Data> Info { get; set; }
}
Upvotes: 1
Reputation: 912
If your xml is missing the info closing tag, meant to contain the Data elements then your classes should look something like:
[XmlRoot(ElementName = "FooBars", Namespace = "http://foos")]
public class FooBars
{
[XmlElement(ElementName = "Id1", Namespace = "http://bars")]
public string Id1 { get; set; }
[XmlElement(ElementName = "Id2", Namespace = "http://bars")]
public string Id2 { get; set; }
[XmlElement(ElementName = "Info", Namespace = "http://bars")]
public Info Information { get;set; }
}
public class Info {
[XmlElement(ElementName = "Data", Namespace = "")]
public Info[] Info { get; set; }
}
public class Data
{
[XmlElement(ElementName = "Field1")]
public string Field1 { get; set; }
[XmlElement(ElementName = "Field2")]
public string Field2 { get; set; }
}
Notice how in your xml the info object basically contains all the data, not the FooBars like you designed the classes.
Upvotes: 0
Reputation: 35477
The XML is missing a closing tag for Info
. Also, you need to defined the Field3
property in the Data
class and add the namespace 'http://bars' to it.
Upvotes: 0