Reputation: 3797
I want to extract the first valid URL in a string, which can be anywhere between characters and whitespace
I have tried with the following
...
urlRegex: /^(http[s]?:\/\/.*?\/[a-zA-Z-_]+.*)$/,
...
var input = event.target.value // <--- some string;
var url = input.match(this.urlRegex);
Problem is url
returns the whole string when it finds a url, instead of returning just the part of the string matching the regex
Example The string
https://medium.com/aspen-ideas/there-s-no-blueprint-26f6a2fbb99c random stuff sd
returns
["https://medium.com/aspen-ideas/there-s-no-blueprint-26f6a2fbb99c random stuff sd", "https://medium.com/aspen-ideas/there-s-no-blueprint-26f6a2fbb99c random stuff sd", index: 0, input: "https://medium.com/aspen-ideas/there-s-no-blueprint-26f6a2fbb99c random stuff sd"]
How can this be achieved?
Upvotes: 3
Views: 23557
Reputation: 14
That's because the match result holds the whole string first that matches, then the groups. I guess you want the group, so you can do this:
url[1]
Here's a fiddle: http://jsfiddle.net/jgt8u6pc/1/
var urlRegex = /^http[s]?:\/\/.*?\/([a-zA-Z-_]+).*$/;
var input = 'http://stackoverflow.com/questions/31760030/extracting-for-url-from-string-using-regex' // <--- some string;
var url = input.match(urlRegex);
$('#one').text(url[0]);
$('#two').text(url[1]);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="one"></div>
<div id="two"></div>
Upvotes: -1
Reputation: 46871
Live Demo with regex explanation on left side.
var regex = /^(https?:\/\/[^/]+(\/[\w-]+)+)/;
var str = 'https://medium.com/aspen-ideas/there-s-no-blueprint-26f6a2fbb99c random stuff sd';
var url = str.match(regex)[0];
document.write(url);
Upvotes: 3
Reputation: 4463
Your regex
is incorrect.
Correct regex for extracting URl : /(https?:\/\/[^ ]*)/
Check out this fiddle.
Here is the snippet.
var urlRegex = /(https?:\/\/[^ ]*)/;
var input = "https://medium.com/aspen-ideas/there-s-no-blueprint-26f6a2fbb99c random stuff sd";
var url = input.match(urlRegex)[1];
alert(url);
Upvotes: 15