Vincent Laufer
Vincent Laufer

Reputation: 705

Error installing pyobjc: Anaconda2.1 python3.4 or 2.7, OSX 10.9

sudo pip install pyobjc returns:

      File "/Users/USER/anaconda/lib/python2.7/subprocess.py", line 573, in check_output
        raise CalledProcessError(retcode, cmd, output=output)
    subprocess.CalledProcessError: Command '['/usr/bin/xcodebuild', '-version', '-sdk', 'macosx', 'Path']' returned non-zero exit status 1

    ----------------------------------------
Command "python setup.py egg_info" failed with error code 1 in /private/var/folders/48/0c48tlds0knggddqs9lwf5900000gn/T/pip-build-RZEwHr/pyobjc-core

while both

easy_install -U pyobjc

and

python install setup.py install

return

xcode-select: error: tool 'xcodebuild' requires Xcode, but active developer directory '/Library/Developer/CommandLineTools' is a command line tools instance
Traceback (most recent call last):
  File "setup.py", line 185, in <module>
    keywords=['Objective-C', 'bridge', 'Cocoa'],

... many more lines of output ... File "/Users/USER/anaconda/lib/python2.7/pickle.py", line 1382, in loads return Unpickler(file).load() File "/Users/USER/anaconda/lib/python2.7/pickle.py", line 858, in load dispatchkey File "/Users/USER/anaconda/lib/python2.7/pickle.py", line 1133, in load_reduce value = func(*args) TypeError: init() takes at least 3 arguments (1 given)

At least a few other people have run into a similar problem: errorr installing pyobjc on Anaconda python on OSX 10.10.2

Has anyone solved it?

Upvotes: 0

Views: 511

Answers (1)

Michiel Kauw-A-Tjoe
Michiel Kauw-A-Tjoe

Reputation: 795

Recent versions of OSX ship with a precompiled PyObjc, if you're able to use the Mac version of Python you should be able to import it: python

Python 2.7.6 (default, Sep  9 2014, 15:04:36) 
[GCC 4.2.1 Compatible Apple LLVM 6.0 (clang-600.0.39)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import objc
>>> objc.__path__
['/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/PyObjC/objc']

Upvotes: 2

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