Reputation: 11
I am new to programming and I am trying to write a program in C for a Caesar Cipher.
Input consists of an integer ilength equal to the length of the string, followed by the string str and an integer encrypt.
My input is:
11
middle-Outz
2
Output:
okffng-Qwv@
Required output is:
okffng-Qwvb
Below is the code I have written. Could someone help me why I am getting the last character wrong in the output!
I'm totally clueless.
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int main()
{
int ilength = 0, encrypt = 0, i = 0, j = 0;
char alph_base[] = {'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'X', 'Y', 'Z', 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'};
scanf("%d", &ilength);
char str[ilength + 1];
scanf("%s", str);
scanf("%d", &encrypt);
//printf("%c\n", str[5]);
char outputString[ilength + 1];
char temp[ilength + 1];
for (j = 0; j <= ilength; j++)
{
temp[j] = str[j];
i = 0;
if (str[j] == '\0')
{
outputString[j] = '\0';
}
while ((i >= 0) && (i < 26))
{
if (temp[j] == alph_base[i])
{
if (i == 25 && encrypt == 0)
{
outputString[j] = alph_base[25];
}
if ((i + encrypt) == 26)
{
outputString[j] = alph_base[(i + encrypt) % 26];
}
else
outputString[j] = alph_base[(i + encrypt) % 26];
}
if ((temp[j] < 65 || temp[j] > 90) && temp[j] < 97)
outputString[j] = temp[j];
if ((temp[j] < 97 || temp[j] > 122) && temp[j] > 90)
outputString[j] = temp[j];
i++;
}
while ((i > 25) && (i < 52))
{
if (temp[j] == alph_base[i])
{
if (i == 51 && encrypt == 0)
{
outputString[j] = alph_base[51];
}
if ((i + encrypt) == 51)
{
outputString[j] = alph_base[51];
}
if ((i + encrypt) > 51)
{
outputString[j] = alph_base[((i + encrypt) % 51) + 25];
}
else
outputString[j] = alph_base[(i + encrypt) % 51];
}
if ((temp[j] < 65 || temp[j] > 90) && temp[j] < 97)
outputString[j] = temp[j];
if ((temp[j] < 97 || temp[j] > 122) && temp[j] > 90)
outputString[j] = temp[j];
i++;
}
}
printf("%s\n", outputString);
return 0;
}
Upvotes: 0
Views: 861
Reputation: 101
Perfect answer by NiBZ. To add to it, if you still want to write your own checks rather than using library functions you can do something like:
int my_isalpha(char c){
return ((c >= 'a' && c <= 'z')|| (c >= 'A' && c <= 'Z'));
}
int my_isupper(char c){
return (c >= 'A' && c <= 'Z');
}
Warning: Above implementation is fine for ASCII but not so good for ISO 8859-1 or its relatives. Ref: https://stackoverflow.com/a/2169293/5183246
Upvotes: 0
Reputation: 532
Your code is too complex for what you want to do.
Your issue seems related to looping back from 'z'
to 'a'
.
A simple function like this can do the work for a character:
#include <ctype.h>
char caesar_encrypt(char input, int key)
{
char output = input;
char base, offset;
// If not a letter, return the char unmodified
if (! isalpha(input))
{
return output;
}
base = isupper(input) ? 'A' : 'a'; // Check if upper/lower case
offset = input - base; // Take offset from 'a'
offset += key; // Add key to offset
offset %= 26; // Wrap offset to the 26 letters
output = base + offset;
return output;
}
Many ideas here:
Use functions from <ctype.h>
(isalpha
, isupper
), which avoids many comparaisons in your code.
Consider your characters as an 'offset' from the letter A (uppercase or lowercase A). Thus you're working with numbers in range [0;25]
, and you can wrap using a simple modulus
Charaters are 'integers', so you can add or subtract them. To get the third letter of the uppercase alphabet, you can do char c = 'A' + 2;
, which is simpler than your huge array.
Disclaimer: Code written here, not tested, may contain typos ;)
Upvotes: 3