Reputation: 3021
I am looking for an easier way to do the following:
m <- matrix(0, nrow=3, 3)
v <- c(1, 3, 2)
for (i in 1:nrow(m)) {
m[[i, v[i]]] = 1
}
The above code creates the following index matrix:
[,1] [,2] [,3]
[1,] 1 0 0
[2,] 0 0 1
[3,] 0 1 0
There surely must be a better way to do this?!
Upvotes: 2
Views: 67
Reputation: 44340
One way to do it without pre-defining the matrix would be to use outer
:
num.col <- 3
outer(v, seq_len(num.col), "==") * 1
# [,1] [,2] [,3]
# [1,] 1 0 0
# [2,] 0 0 1
# [3,] 0 1 0
Upvotes: 2