Reputation: 1798
Suppose to have a collection of MongoDB documents with the following structure:
{
id_str: "some_value",
text: "some_text",
some_field: "some_other_value"
}
I would like to filter such documents so as to obtain the ones with distinct text values.
I learned from the MongoDB documentation how to extract unique field values from a collection, using the distinct
operation. Thus, by performing the following query:
db.myCollection.distinct("text")
I would obtain an array containing the distinct text values:
["first_distinct_text", "second_distinct_text",...]
However, this is not the result that i would like to obtain. Instead, I would like to have the following:
{ "id_str": "a_sample_of_id_having_first_distinct_text",
"text": "first_distinct_text"}
{ "id_str": "a_sample_of_id_having_second_distinct_text",
"text": "second_distinct_text"}
I am not sure if this can be done with a single query.
I found a similar question which, however, do not solve fully my problem.
Do you have any hint on how to solve this problem?
Thanks.
Upvotes: 2
Views: 2120
Reputation: 879
You should look into making an aggregate query using the $group
stage, and probably using the $first
operator.
Maybe something along the lines of:
db.myCollection.aggregate([{ $group : { _id : { text: "$text"},
text: { $first: "$id_str" }
}
}])
Upvotes: 2
Reputation: 479
try:
db.myCollection.aggregate({$group: {_id: {'text': "$text", 'id_str': '$id_str'}}})
More information here: http://docs.mongodb.org/manual/reference/method/db.collection.aggregate/
Upvotes: 0