Reputation: 945
I simply use
IOUtils.copy(myInputStream, myOutputStream);
And I see that before calling IOUtils.copy the input stream is avaible to read and after not.
flux.available()
(int) 1368181 (before)
(int) 0 (after)
I saw some explanation on this post, and I see I can copy the bytes
from my InputStream
to a ByteArrayInputStream
and then use mark(0)
and read()
, in order to read multiple times an input stream.
Here is the code resulted (which is working). I find this code very verbose, and I'd like if there is a better solution to do that.
ByteArrayInputStream fluxResetable = new ByteArrayInputStream(IOUtils.toByteArray(myInputStream));
fluxResetable.mark(0);
IOUtils.copy(fluxResetable, myOutputStream);
fluxResetable.reset();
Upvotes: 1
Views: 6398
Reputation: 49804
An InputStream
, unless otherwise stated, is single shot: you consume it once and that's it.
If you want to read it many times, that isn't just a stream any more, it's a stream with a buffer. Your solution reflects that accurately, so it is acceptable. The one thing I would probably change is to store the byte array and always create a new ByteArrayInputStream
from it when needed, rather than resetting the same one:
byte [] content = IOUtils.toByteArray(myInputStream);
IOUtils.copy(new ByteArrayInputStream(content), myOutputStream);
doSomethingElse(new ByteArrayInputStream(content));
The effect is more or less the same but it's slightly easier to see what you're trying to do.
Upvotes: 9