CODEWITHSUNDEEP
javaperformancehibernatejdbcorm
tharindu_DG
tharindu_DG

Reputation: 9291

Hibernate : JDBC Vs Hibernate Performance in bulk records

Description : LoadoutOperatingSession represents a particular time period and it belongs to a certain loadoutId. There can be a lot of LoadoutOperatingSession objects with the same loadoutId

Before inserting a new session, a check had to be performed for overlappings.

Below is the model object that I have designed.

public class LoadoutOperatingSession extends Entity implements Serializable, Comparable<LoadoutOperatingSession>{

private Long loadoutId;
private Date effectiveFromDate;
private Date effectiveToDate;
private String sessionStartTime;
private String sessionEndTime;
private String isSchedule;


/**
 *  Compares the given session with the current one and return 1 if this session is greater than the given session,
 * -1 if the this session is less than the given session and
 *  0 is the sessions are overlapping.
 *  
 * @param  session1
 *         First Session
 *         
 * @param session
 *         Second Session
 */

@Override
public int compareTo(LoadoutOperatingSession session) {

    if (session.getEffectiveToDate().getTime() < this.getEffectiveFromDate().getTime()) {
        return 1;
    } else if (this.getEffectiveToDate().getTime() < session.getEffectiveFromDate().getTime()) {
        return -1;
    } else if (this.getEffectiveFromDate().getTime() == session.getEffectiveFromDate().getTime()) {

        int thisStartTime = Integer.parseInt(this.getSessionStartTime());
        int thisEndTime = Integer.parseInt(this.getSessionEndTime());

        int sessionStartTime = Integer.parseInt(session.getSessionStartTime());
        int sessionEndTime = Integer.parseInt(session.getSessionEndTime());

        if (thisEndTime < sessionStartTime) {
            return -1;
        } else if (thisStartTime > sessionEndTime) {
            return 1;
        }
        return 0;
    }
    return 0;
}

}

Assume there are lots of LoadoutOperatingSession objects with the same loadoutId. In order to check for overlaps, I have fetched all the LoadoutOperatingSession objects and used the compareTo method to compare with each other.

Note : This check is done before persisting the current Session.

fetchLoadoutOperatingSessionsList method will return all the LoadoutOperatingSession Objects for a given loadoutId

validateForOverlappings(model, fetchLoadoutOperatingSessionsList(model));

private <T extends Comparable> void validateForOverlappings(T obj, List<T> objList){        

    for (Comparable c : objList) {
        if(obj.compareTo((T) c) == 0){
            throw new IllegalArgumentException("Overlapping Sessions are not allowed!");
        }
    }
}

Question : This same validation can be done by executing a JDBC query and taking a count of the overlapping sessions.

Would it be more efficient than the above mentioned java solution?

Please Justify.

Upvotes: 1

Views: 287

Answers (1)

Jan Hruby
Jan Hruby

Reputation: 1497

Using this SQL statement it is possible to perform the check on DB level:

select top 1 a.id 
from LoadoutOperatingSession a, LoadoutOperatingSession b 
where a.FROM_DATE <= b.TO_DATE and b.FROM_DATE <= a.TO_DATE

Why is it faster:

  • it is same as on application level. SQL returns first overlapping record
  • BUT, you are not returning list of records from DB, but simple integer - no serialization overhead

However I think there is something else wrong if you are throwing IllegalArgument on application level after validating records which are read from DB. I do not know your use case but it would be much safer to prevent saving such records

EDIT

My previous answer was not correct. This is the equal check done on DB level

select top 1 a.id 
from LoadoutOperatingSession a 
where a.FROM_DATE <= :insertedStartDate and a.TO_DATE >= :insertedEndDate

Upvotes: 2

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