CODEWITHSUNDEEP
linuxbashshelljulia
AKS
AKS

Reputation: 17336

Julia - How Julia processes a variable?

I'm just starting to learn Julia. I'm using JuliaBox (browser based session).

Seems like most of the shell commands (in BASH works) in Julia's shell.

But, I didn't get why in BASH Shell/Julia shell, it didn't print $c (in the example below) first time but it works later on (after I did some operation on $v variable). How's Julia shell processes this behavior?

enter image description here

PS: I know if I want to print $c first time, I have to use echo $((c))

Upvotes: 0

Views: 153

Answers (1)

choroba
choroba

Reputation: 241988

This seems like the normal bash behaviour. ((...)) is used for arithmetic evaluation, without it, everything on the right hand side is a string. $((...)) does arithmetic expansion, which means it expands to the result of the arithmetic expression. See man bash.

Upvotes: 3

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