Read file into array with empty lines

Question

I'm using this code to load file into array in bash:

IFS=$'\n' read -d '' -r -a LINES < "$PAR1"

But unfortunately this code skips empty lines.

I tried the next code:

IFS=$'\n' read -r -a LINES < "$PAR1"

But this variant only loads one line.

How do I load file to array in bash, without skipping empty lines?

P.S. I check the number of loaded lines by the next command:

echo ${#LINES[@]}

Answer 1

To avoid doing anything fancy, and stay compatible with all versions of bash in common use (as of this writing, Apple is shipping bash 3.2.x to avoid needing to comply with the GPLv3):

lines=( )
while IFS= read -r line; do
  lines+=( "$line" )
done

See also BashFAQ #001.

Answer 2

You can use mapfile available in BASH 4+

mapfile -t lines < "$PAR1"