CODEWITHSUNDEEP
pythondjangodjango-formshttpresponse
ted
ted

Reputation: 14744

How to clear a form but still display one of its fields?

I'd like to submit a form F, clear its fields, but still display one of its fields. F submits to a view that renders the very template that first displayed it

To do so, I return a HttpResponseRedirect object instead of rendering a template with the request :

def home(request):

    if request.method == 'POST':
        form = New_mini_url_form(request.POST)
        if form.is_valid():
            if (MiniUrl.objects.filter(url=form.cleaned_data['url']).count() == 0):
                code = form.cleaned_data['code']
                request.session["code"] = code
                [... stuff ...]

                return HttpResponseRedirect(reverse(home))

            else:
                code = form.cleaned_data['code']
                request.session["code"] = code
                [... stuff ...]

                return HttpResponseRedirect(reverse(home))
        else:
            return render(request, 'mini_url/home.html', locals())

    else:
        form = New_mini_url_form()
        return render(request, 'mini_url/home.html', locals())

and I have {{ request.session.code}} in my template

Here is an extracts of project/settings.py

TEMPLATE_CONTEXT_PROCESSORS = (
    "django.contrib.auth.context_processors.auth",
    "django.core.context_processors.debug",
    "django.core.context_processors.i18n",
    "django.core.context_processors.media",
    "django.core.context_processors.static",
    "django.core.context_processors.tz",
    "django.contrib.messages.context_processors.messages",
    "django.core.context_processors.request"
)

Thanks!

Upvotes: 0

Views: 37

Answers (1)

Rahul Gupta
Rahul Gupta

Reputation: 47876

You can set the code variable in the session. Then access it using request.session.code in your template.

def home(request):

    if request.method == 'POST':
        form = New_mini_url_form(request.POST)
        if form.is_valid():
            if (MiniUrl.objects.filter(url=form.cleaned_data['url']).count() == 0):
                code = form.cleaned_data['code']
                request.session['code'] = code # set code in the session
                [... stuff ...]

                return HttpResponseRedirect(reverse(home))

            else:
                code = form.cleaned_data['code']
                request.session['code'] = code # set code in the session
                [... stuff ...]

                return HttpResponseRedirect(reverse(home))
        else:
            return render(request, 'mini_url/home.html', locals())

    else:
        form = New_mini_url_form()
        return render(request, 'mini_url/home.html', locals())

Then in your template, you can access code by:

{{request.session.code}} # display code in the template

You must include django.core.context_processors.request in the settings.

TEMPLATE_CONTEXT_PROCESSORS = (
  ...
  'django.core.context_processors.request', # will pass request in the template
  ...
)

From Django 1.7 docs on request context processor:

django.core.context_processors.request

If TEMPLATE_CONTEXT_PROCESSORS contains this processor, every RequestContext will contain a variable request, which is the current HttpRequest. Note that this processor is not enabled by default; you’ll have to activate it.

Upvotes: 1

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