CODEWITHSUNDEEP
pythonlistindexing
Hackxx
Hackxx

Reputation: 71

Python index function inquiry

If I have a name = 'Peter Piper Picker' and I want my function to selective isolate 'Picker', what would I have to do? I don't mean like name[12:], but like where it picks out where the last space before the end of the name is and starts substring-ing from there? I know index function has two additional parameters, but I don't know how they can be applied properly in this setting I was thinking name[' ', name.split(len(name.split()-1)), name[len(name)-1]].

Upvotes: 1

Views: 204

Answers (4)

liushuaikobe
liushuaikobe

Reputation: 2190

You could use the split method of str.

name = 'Peter Piper Picker' 
# name.split() will return a list ['Peter', 'Piper', 'Picker'], we need its last element   
ret = name.split()[-1]

Then ret is 'Picker'.

Upvotes: 5

bagrat
bagrat

Reputation: 7418

The cryptic way:

>>> name[[i for i, c in enumerate(name) if c == ' '][-1]+1:]
'Picker'
  • [i for i, c in enumerate(name) if c == ' '] - this will get you all the indexes where there is a space (' ') in your string
  • [i for i, c in enumerate(name) if c == ' '][-1] - this will get you the index of the last space
  • [i for i, c in enumerate(name) if c == ' '][-1]+1 - this one is the position where you desired name part starts

And finally you slice your name.

Upvotes: 1

The6thSense
The6thSense

Reputation: 8335

You could also do:

name = 'Peter Piper Picker'
name.rsplit(" ",1)[1]
'Picker'

When using rsplit you will get the following output:

name.rsplit(" ",1)
['Peter Piper', 'Picker']

Process:

You are splitting from the right and you are splitting once using " " and getting the second element

Information:

For more on rsplit look into rsplit official document

Upvotes: 4

yask
yask

Reputation: 4268

>>> name = 'Peter Piper Picker'
>>> a = name.split()
>>> a[len(a)-1]
'Picker'

Upvotes: 3

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