CODEWITHSUNDEEP
pythonlinuxbashsubprocessstdout
G Warner
G Warner

Reputation: 1379

Capture output of bash code run in python

I'm trying to capture the output of a bash line I'm executing in my python script using the following code:

call_bash = subprocess.Popen(['/space/jazz/1/users/gwarner/test.sh'],stdout=subprocess.PIPE)
output = call_bash.communicate()[0]

This works fine but I'd like to change it so that that bash code is written directly into this python script (eliminating the need for a separate .sh file). I know that I can run bash code from python with subprocess.call() but I can't figure out how to capture the output (what normally gets printed to the terminal incase I'm using the wrong terminology). Can anyone help?

I'm running python 2.7 on CentOS

Upvotes: 0

Views: 1579

Answers (1)

Eric Renouf
Eric Renouf

Reputation: 14520

The first argument to subprocess.Popen is a list of arguments (unless you specify shell=True).

So you could do your example like

call_bash = subprocess.Popen(['ssh', '[email protected]', 'scp me#comp:/~/blah.text ep#comp:/register/'], stdout=subprocess.PIPE)
output = call_bash.communicate()[0]

This will invoke the ssh command with 2 arguments, [email protected] and scp me#comp:/~/blah.text ep#comp:/register/.

Upvotes: 2

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