CODEWITHSUNDEEP
pythonpython-2.7
Riaz Ladhani
Riaz Ladhani

Reputation: 4062

TypeError: next expected at least 1 arguments, got 0 I am trying to iterate through csv file

I have the following code to iterate through a csv file. Iterate using the last column of in the csv file, column 11

I get the following error:

TypeError: next expected at least 1 arguments, got 0

The code is:

    from operator import itemgetter
import os
import csv

reader = csv.reader(open('file1.csv','rb'))
#header = reader.next()
header = next().reader
data = list(reader)
reader = None
data.sort(key=itemgetter(11))

writer = csv.writer(open('2.csv', 'wb'))
writer.writerow(header)
writer.writerows(data)

I think it is complaining about the header.

Upvotes: 0

Views: 16291

Answers (1)

Martijn Pieters
Martijn Pieters

Reputation: 1122102

You need to pass reader as an argument to the next() function:

header = next(reader)

or you could call the iterator.next() method on the reader object:

header = reader.next()

I recommend sticking to the first spelling, especially since you can tell it to return None (or another default) if the CSV file is empty:

header = next(reader, None)

Upvotes: 3

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