CODEWITHSUNDEEP
pythonpandas
ZK Zhao
ZK Zhao

Reputation: 21513

Python & Pandas: Combine columns into a date

In my dataframe, the time is separated in 3 columns: year, month, day, like this: enter image description here

How can I convert them into date, so I can do time series analysis?

I can do this:

df.apply(lambda x:'%s %s %s' % (x['year'],x['month'], x['day']),axis=1)

which gives: 

1095       1954 1 1
1096       1954 1 2
1097       1954 1 3
1098       1954 1 4
1099       1954 1 5
1100       1954 1 6
1101       1954 1 7
1102       1954 1 8
1103       1954 1 9
1104      1954 1 10
1105      1954 1 11
1106      1954 1 12
1107      1954 1 13

But what follows?

EDIT: This is what I end up with:

from datetime import datetime
df['date']= df.apply(lambda x:datetime.strptime("{0} {1} {2}".format(x['year'],x['month'], x['day']), "%Y %m %d"),axis=1)
df.index= df['date']

Upvotes: 13

Views: 12601

Answers (3)

Marc Garcia
Marc Garcia

Reputation: 3497

There is a simpler and much faster way to convert 3 columns with year, month and day to a single datetime column in pandas:

import pandas

pandas.to_datetime(df)

Besides the code being much simpler than the accepted answer, in my computer your implementation takes 22.3 seconds, while this one takes 175 milliseconds, with a 1 million rows dataframe. This implementation is 127x faster.

Note that in your case, the columns are already named year, month and day, which is a requirement for the input dateframe of to_datetime. If they have different names, you need to rename them first (e.g. df.rename(columns={'<your_year_col>': 'year', ...})).

Upvotes: 2

Cl&#233;ment
Cl&#233;ment

Reputation: 12897

It makes no sense to format a date to a string and immediately reparse it; use the datetime constructor instead:

df.apply(lambda x: datetime.date(x['year'], x['month'], x['day']), axis=1)

Upvotes: 4

FirebladeDan
FirebladeDan

Reputation: 1069

Here's how to convert value to time:

import datetime


df.apply(lambda x:datetime.strptime("{0} {1} {2} 00:00:00".format(x['year'],x['month'], x['day']), "%Y %m %d %H:%M:%S"),axis=1)

Upvotes: 9

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