CODEWITHSUNDEEP
javaservlets
Sunny
Sunny

Reputation: 286

Get display name from web.xml file

I am trying to get the Display name (Context Root) from web.xml file to avoid hardcoding a context root.

Any help would be appreciated.

Upvotes: 7

Views: 9450

Answers (3)

Ronald Coarite
Ronald Coarite

Reputation: 4736

En nombre puede obtener de la clase ServletContext. Con JSF

ExternalContext externalContext = FacesContext.getCurrentInstance().getExternalContext();
ServletContext servletContext= (ServletContext) externalContext.getContext();
System.out.println("Context Name: "+servletContext.getServletContextName());

Or Within a Servlet

protected void doGet(HttpServletRequest request, HttpServletResponse response)
{
ServletContext servletContext= getServletContext();
System.out.println("Context Name: "+servletContext.getServletContextName());
}

Upvotes: 1

BalusC
BalusC

Reputation: 1108922

There's some ambiguity in your question. The "display name" is not the same as "context root". To get the <display-name> value from web.xml, look at skaffman's answer in this question. To get the <Context path> value from context.xml, use ServletContext#getContextPath(). This is often referenced as "context root" (which you also see in the URL, that part immediately after domain).

Upvotes: 12

skaffman
skaffman

Reputation: 403501

ServletContext.getServletContextName()

Returns the name of this web application corresponding to this ServletContext as specified in the deployment descriptor for this web application by the display-name element.

Upvotes: 12

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