CODEWITHSUNDEEP
sqlsql-serverguiduniqueidentifier
Muthukamatchi Ganesan
Muthukamatchi Ganesan

Reputation: 373

Guid with extra characters issue

I have a table named Student, contain a column StudentId as GUID, so I used the Uniqueidentifier datatype for that.

If I want to get particular record, I get the result by the below query:

SELECT * FROM Student WHERE StudentId = '919C3BF9-B081-458C-897D-C0B3FF56AF73'

It returns the expected result. But in case if I mistakenly add any extra characters in the end also, it returns the same result. Like the below query:

SELECT * FROM Student WHERE StudentId = '919C3BF9-B081-458C-897D-C0B3FF56AF73xyz'

If I pass the extra characters in the end of GUID, why it is not consider as invalid GUID? and return the same result?

Upvotes: 6

Views: 2864

Answers (2)

avi
avi

Reputation: 912

As stated from the documentation:

The following example demonstrates the truncation of data when the value is too long for the data type being converted to. Because the uniqueidentifier type is limited to 36 characters, the characters that exceed that length are truncated.

DECLARE @ID nvarchar(max) = N'0E984725-C51C-4BF4-9960-E1C80E27ABA0wrong';
SELECT @ID, CONVERT(uniqueidentifier, @ID) AS TruncatedValue;

Here is the result set.

String                                       TruncatedValue
-------------------------------------------- ------------------------------------
0E984725-C51C-4BF4-9960-E1C80E27ABA0wrong    0E984725-C51C-4BF4-9960-E1C80E27ABA0

(1 row(s) affected)

Upvotes: 3

Arulkumar
Arulkumar

Reputation: 13247

GUID is 16 bytes, so from the given 919C3BF9-B081-458C-897D-C0B3FF56AF73

91 is 1st byte
9C is 2nd byte
3B is 3rd byte
F9 is 4th byte
..
..
..
..
56 is 14th byte
AF is 15th byte
73 is 16th byte

Parsing of 919C3BF9-B081-458C-897D-C0B3FF56AF73xyz completes before the xyz.

So the characters are entered after the 16th byte, won't be consider.

But if you add any extra characters in the front, it won't consider as valid GUID.

Moreover, when you query with GUID, use the code in between the {}.

SELECT * FROM Student 
WHERE StudentId = '{919C3BF9-B081-458C-897D-C0B3FF56AF73}'

Upvotes: 3

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