CODEWITHSUNDEEP
c#coordinates
user278618
user278618

Reputation: 20222

Convert decimal coordinates to Degrees, Minutes & Seconds by c#

Has anyone know simple short code to convert this without use additional libraries ?

Upvotes: 1

Views: 13924

Answers (5)

Charles Bretana
Charles Bretana

Reputation: 146409

you could use timespan: (tricky but it works)

   double coord = 123.312312;   
   var ts = TimeSpan.FromHours(Math.Abs(coord));
   int degrees = Math.Sign(coord) * Math.Floor(ts.TotalHours);
   int minutes = ts.Minutes;
   int seconds = ts.Seconds;

Upvotes: 4

maf-soft
maf-soft

Reputation: 2552

String representation of a location, i.e. 51°09'48.2"N 10°07'28.6"E

public static string ToDMS(this Location location)
{
    var (lat, lon) = (location.Latitude, location.Longitude);
    var latSec = Math.Abs(lat) % 1.0 * 3600.0;
    var lonSec = Math.Abs(lon) % 1.0 * 3600.0;
    return FormattableString.Invariant(
      $@"{Math.Abs((int)lat)}°{(int)latSec / 60}'{latSec % 60:F1}\"{(lat >= 0 ? "N" : "S")
       } {Math.Abs((int)lon)}°{(int)lonSec / 60}'{lonSec % 60:F1}\"{(lon >= 0 ? "E" : "W")}");
}

You might not like this one-liner :)

public static string ToDMS(double lat, double lon) => FormattableString.Invariant($"{Math.Abs((int)lat)}°{(int)(Math.Abs(lat) % 1.0 * 60.0)}'{Math.Abs(lat) * 3600.0 % 60:F1}\"{(lat >= 0 ? "N" : "S")} {Math.Abs((int)lon)}°{(int)(Math.Abs(lon) % 1.0 * 60.0)}'{Math.Abs(lon) * 3600.0 % 60:F1}\"{(lon >= 0 ? "E" : "W")}" );

Suggestions for any improvements welcome...

Upvotes: 0

Brian Gideon
Brian Gideon

Reputation: 48949

I came up with the following. It correctly handles negative coordinates (south latitude or west longitude) and returns the remainder (in degrees) that was not evely divided into minutes or seconds.

public static double ConvertDecimalToDegMinSec(double value, out int deg, out int min, out int sec)
{
    deg = (int)value;
    value = Math.Abs(value - deg);
    min = (int)(value * 60);
    value = value - (double)min / 60;
    sec = (int)(value * 3600);
    value = value - (double)sec / 3600;
    return value;
}

Upvotes: 2

Guffa
Guffa

Reputation: 700152

Like this:

double coord = 59.345235;
int sec = (int)Math.Round(coord * 3600);
int deg = sec / 3600;
sec = Math.Abs(sec % 3600);
int min = sec / 60;
sec %= 60;

Edit: Added an Abs call so that it works for negative angles also.

Upvotes: 9

Ragster
Ragster

Reputation: 717

I am infering from your question that you want to convert from cartesian to polar coordinates.

If this is the case, the basic formulae you need are:

r = √ (x2 + y2)

θ = atan( y / x )

Where r is the distance and θ is the angle from x = 0 (about the origin)

Does this help?

Upvotes: 2

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