CODEWITHSUNDEEP
rubyconcurrencyfibers
Sagar Pandya
Sagar Pandya

Reputation: 9497

Fiber.yield using ||

I would like some help with the following code:

sg = Fiber.new do
    s = 0
    loop do
        square = s * s
        s += 1
        s = Fiber.yield(square) || s
    end
end

puts sg.resume
puts sg.resume
puts sg.resume
puts sg.resume 40
puts sg.resume
puts sg.resume 0
puts sg.resume
puts sg.resume

When run, outputs:

0
1
4
1600
1681
0
1
4

How does line 6 s = Fiber.yield(square) || s work? I think I understand the component parts just not what the line as a whole is doing. (Is there an alternative way of writing this that might better help me understand?).

(Edit: This code is a very slightly modified example from page 295 'Beginning Ruby, From Novice to Professional 2nd Ed' by Peter Cooper.)

Upvotes: 1

Views: 255

Answers (1)

Stefan
Stefan

Reputation: 114178

According to the docs for yield

Any arguments passed to the next resume will be the value that this Fiber.yield expression evaluates to.

The line

s = Fiber.yield(square) || s

assigns the argument passed to resume to s. If that value is nil (or the argument is missing), s is re-assiged to s (i.e. it doesn't change).

Example:

sg.resume       #=> s = nil || s
                #=> s = s

sg.resume 40    #=> s = 40  || s
                #=> s = 40

Another way to write it is:

result = Fiber.yield(square)
s = result if result

Upvotes: 2

Related Questions