Reputation: 814
Is it possible to have the same width on all cells in a table that is equal to the widest cell's width without using fixed widths.
Upvotes: 4
Views: 2090
Reputation: 4971
Yes it is.
<table>
<tr>
<td>short</td>
<td>longer</td>
<td>the longest cell</td>
</tr>
</table>
var max = 0,
$cells = $('td');
$cells.each(function () {
var width = $(this).width();
max = max < width ? width : max;
});
$cells.each(function () {
$(this).width(max);
});
https://jsfiddle.net/uqvuwopd/1/
[EDIT]
As @connexo pointed out in the comments some more logic is needed to handle the case when the table would be larger than its maximum size:
var max = 0,
$cells = $('td');
$cells.each(function () {
var width = $(this).width();
max = max < width ? width : max;
});
$table = $cells.closest('table');
if ($table.width() < max * $cells.length) {
max = 100 / $cells.length + '%';
}
$cells.each(function () {
$(this).width(max);
});
https://jsfiddle.net/uqvuwopd/3/
[EDIT]
And this is a version based on ECMA5 that doesn't require jQuery:
var max = 0,
cells = document.querySelectorAll('td');
Array.prototype.forEach.call(cells, function(cell){
var width = cell.offsetWidth;
max = max < width ? width : max;
});
var table = document.querySelector('table'),
uom = 'px';
if (table.offsetWidth < max * cells.length) {
max = 100 / cells.length;
uom = '%';
}
Array.prototype.forEach.call(cells, function(cell){
cell.setAttribute('style','width:' + max + uom);
});
https://jsfiddle.net/uqvuwopd/4/
Upvotes: 6