CODEWITHSUNDEEP
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SilentDev
SilentDev

Reputation: 22777

CodeIgniter / PHP: How to get URI in .php view page

I came across a similar issue as this user: How to add active class to codeigniter hyperlinks?

and the answer was to insert the following into the .php view page:

<a class="<?php if($this->uri->segment(1)=="search"){echo "active";}?>" href="<?=base_url('search')?>">
        <i class="icon-search"></i>
        <span>BEDRIJF ZOEKEN</span>
</a>

When I insert this into my page, even if my URL is "search" it does not assign the class "active" to the link tag. I tried doing this:

<?php 
$uri = $this->uri->segment(1);
echo "<script type='text/javascript'>alert('$uri');</script>";
?>

and it alerts nothing (the alert box does not display anything). I also tried alerting the following:

$this->uri->uri_string()

and I get the same result (an empty alert box). What am I missing?

Edit: My controller is Pages.php:

<?php
class Pages extends CI_Controller {

    public function view($page = 'home') {

        if ( ! file_exists(APPPATH.'/views/pages/'.$page.'.php'))
        {
            // Whoops, we don't have a page for that!
            show_404();
        }

        $data['title'] = ucfirst($page); // Capitalize the first letter
        $this->load->view('templates/header', $data);
        $this->load->view('pages/'.$page, $data);
        $this->load->view('templates/footer', $data);
    }

}
?>

Upvotes: 4

Views: 1318

Answers (2)

Chintan7027
Chintan7027

Reputation: 7615

As i have seen you are trying to apply current menu as class='active'. My sugesstion to you is that rather than finding uri and matching it. You can use following method to your controller and view.

Controller

$data['active_menu'] ='search' or

$data['active_menu'] ='home' or

$data['active_menu'] ='help'

   `$this->load->view('templates/header', $data);
    $this->load->view('pages/'.$page, $data);
    $this->load->view('templates/footer', $data);`

View Pages (Home_view.php/search_view.php/help_view.php)

<a class="<?php if($active_menu=="search"){echo "active";}?>" href="<?=base_url('Pages')?>"> <i class="icon-search"></i> <span>BEDRIJF ZOEKEN</span> </a>

Upvotes: 2

Abdulla Nilam
Abdulla Nilam

Reputation: 38672

Try this

<a class="<?php if($this->uri->segment(1)=="Pages"){echo "active";}?>" href="<?=base_url('Pages')?>">
        <i class="icon-search"></i>
        <span>BEDRIJF ZOEKEN</span>
</a>

$this->uri->segment(1) means www.example.com/Pages/my_Method

  1. Base URL = www.example.com
  2. $this->uri->segment(1) = Pages
  3. $this->uri->segment(2) = my_Method

Upvotes: 3

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