Reputation: 467
I have the following text file and I want to retrieve the numbers in brackets
ID&number:Track_number(12930)_
ID&number:Track_number(394839)_
ID&number:Track_number(958236)_
So I've tried this
import re
file = open("text.txt", "r")
text = file.read()
file.close()
pattern = re.compile(ur'Track_number(.*)_', re.UNICODE)
string = pattern.search(text).group(1)
print string
But it only displays the first result : (12930)
.
I was wondering if it was possible to have a list of all the matching results.
Thanks
Upvotes: 4
Views: 78
Reputation: 49320
All you have to do is replace that search
with findall
. This will produce a list
of all the matches.
Upvotes: 1
Reputation: 117856
You can use re.findall
for example
>>> re.findall('\((\d+)\)', text)
['12930', '394839', '958236']
Upvotes: 2