CODEWITHSUNDEEP
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Den3243
Den3243

Reputation: 161

Swift replace first character in string

A very simple question, how do I replace the first character of a string. I'm probably doing something totally wrong, but I simply can't get it to work.

I have tried this: var query = url.query!.stringByReplacingOccurrencesOfString("&", withString: "?", options: NSStringCompareOptions.LiteralSearch, range: NSMakeRange(0, 1))

But it gives me the following error:

Cannot invoke 'stringByReplacingOccurrencesOfString' with an argument list of type '(String, withString: String, options: NSStringCompareOptions, range: NSRange)'

When I remove the NSMakeRange and change it to nil, it works, but it replaces all the &'s in the string.

Upvotes: 9

Views: 22487

Answers (8)

Cruz
Cruz

Reputation: 2632

Another answer

Use suffix

var s = "1234567"
var transform = "?" + s.suffix(max(s.count - 1, 0))
transform // "?234567"

Upvotes: 0

Leo Dabus
Leo Dabus

Reputation: 236340

Swift 4 or later

let string = "&whatever"
let output = "?" + string.dropFirst()

mutating the string

var string = "&whatever"
if !string.isEmpty {
    string.replaceSubrange(...string.startIndex, with: "?")
    print(string)  // "?whatever\n"
}

Upvotes: 24

Hassan Badawi
Hassan Badawi

Reputation: 302

Swift 4.0

extension String
{
    func replace_fromStart(str:String , endIndex:Int , With:String) -> String {
        var strReplaced = str ;
        let start = str.startIndex;
        let end = str.index(str.startIndex, offsetBy: endIndex);
        strReplaced = str.replacingCharacters(in: start..<end, with: With) ;
        return strReplaced;
    }
}

use it any where

MY_String.replace_fromStart(str: MY_String, endIndex: 10, With: "**********")

Upvotes: 0

MirekE
MirekE

Reputation: 11555

You can try this:

var s = "123456"

let s2 = s.replacingCharacters(in: ...s.startIndex, with: "a")

s2 // "a23456"

Upvotes: 19

Warrior
Warrior

Reputation: 39374

In Swift 4.0

let inputString = "!Hello"
let outputString = String(inputString.dropFirst())

Answer

outputString = "Hello"

Upvotes: 2

Aadi007
Aadi007

Reputation: 247

In Swift 2.0 you can do something like this:-

let inputString = "!Hello"
let outputString = String(inputString.characters.dropFirst())

//Answer
outputString = "Hello"

Upvotes: 0

Mundi
Mundi

Reputation: 80265

let range = Range(start: query.startIndex, end: query.startIndex.successor())
query.replaceRange(range, with: "?")

or shorter

let s = query.startIndex
query.replaceRange(s...s, with: "?")

This is a bit different from Objective-C - but we will get used to it I guess ;-).

If you are uncomfortable with this, you can always drop back to the old NSString APIs:

let newQuery = (query as NSString).stringByReplacingCharactersInRange(
  NSMakeRange(0,1), withString: "?") // as String not necessary

Upvotes: 4

Palle
Palle

Reputation: 12109

The problem is that you are passing an NSRange value, where a Range object is expected. When using Swift strings, you have to use 

Range<String.Index>(start: str.startIndex, end: advance(str.startIndex, 1))

Upvotes: 0

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