Reputation: 262
temp1 is "accountant"editText is "accountant"
but i checked with String.length();
I tried trim() method, i got the same result again.
Code sample:
if(temp1.equalsIgnoreCase(editText1.getText().toString().trim()))
{
//do someting
}
I solved.
Upvotes: 0
Views: 1152
Reputation: 169
You may try this code :
//put this below public class activity
int index=0;
String [] answer ={"Accountant"};
and put this button code below setContentView
buttonanswer = (Button)findViewById(R.id.yourbutton);
buttonanswer.setOnClickListener(this);
and then put this code
@Override
public void onClick(View v) {
edittextanswer=(EditText)findViewById(R.id.youreditText);
if(v==buttonanswer) {
String myanswer=edittextanswer.getText().toString();
if(myanswer.equalsIgnoreCase(answer[index]))
{
//do someting
}
else
{
//do someting
}
Upvotes: 0
Reputation: 571
Since temp1
is a string and has 11 characters, you must have placed a whitespace after the word accountant. (Either that or you flat out misspelled the word.) Accountant is only 10 characters long, so there must be whitespace. (Well, it's pretty guaranteed since you, yourself, created it.)
Either remove the whitespace from temp1
, or trim temp1
before you compare.
Also, double-check temp1
to actually make sure you spelled the word correctly.
Upvotes: 2