Reputation: 1079
In the chapter Lifetimes of the Rust book, there's an example:
struct Foo<'a> {
x: &'a i32,
}
fn main() {
let y = &5; // this is the same as `let _y = 5; let y = &_y;`
let f = Foo { x: y };
println!("{}", f.x);
}
Why do they use x: &'a i32
?
I think if it is just x: i32
then they cannot demonstrate the lifetime usage. However, is there any other reason behind it? Is there any production code that uses immutable reference to a primitive type like i32?
Upvotes: 9
Views: 1835
Reputation: 128161
In this particular case the reason is indeed to show the concept of lifetimes. As for the general case, however, I see no reason making an immutable reference to a primitive type (mutable references, of course, is another matter) except of when it is done in generic code:
struct Holder<'a, T> {
r: &'a T
}
let x: i32 = 123;
let h: Holder<i32> = Holder { r: &x };
Here if you have such structure, you have no other choice as to use a reference to an i32
. Naturally, this structure can also be used with other, non-primitive and non-movable types.
As Shepmaster has mentioned in comments, there is indeed a case where you have references to primitive types - it is by-reference iterators. Remember, by a convention (which the standard library follows) iter()
method on a collection should return an iterator of references into the collection:
let v: Vec<i32> = vec![1, 2, 3, 4];
let i = v.iter(); // i is Iterator<Item=&i32>
Then almost all methods on the iterator which take a closure will accept closures whose argument is a reference:
i.map(|n| *n + 1) // n is of type &i32
Note that this is in fact a consequence of the more general case with generics. Vectors and slices may contain arbitrary types, including non-moveable ones, so they just have to have methods which would allow their users to borrow their contents.
Upvotes: 11