CODEWITHSUNDEEP
java
Pat Eckert
Pat Eckert

Reputation: 3

CodeModel Interface creation Java

I am currently working on dynamic java source code creation and I ran into a problem. Everything is working fine so far but not with interfaces.

UMLClass = codemodel._class(JMod.PUBLIC, umlInterface.getName(), ClassType.INTERFACE);

//UMLClass is a JDefinedClass, umlInterface.getName() is just a String

If I try running this code, it creates source code looking like this:

public class Bull {

    private final static long bli;
    private final static double bla;

    abstract void abstractOperation();
}

It doesn't name it interface and I have not figured out, why, because the JType was set to INTERFACE which should create an interface?

Upvotes: 0

Views: 485

Answers (1)

Alin Pandichi
Alin Pandichi

Reputation: 955

It's a bug in CodeModel:

JCodeModel._class(fullyqualifiedName, ClassType.INTERFACE) create a concrete class if fullyqualifiedName is in root package. When calling jCodeModel._class(fullyqualifiedName, ClassType.INTERFACE),if fullyqualifiedName does not have a ".", the classtype is set to CLASS.

https://github.com/javaee/jaxb-codemodel/issues/24

So you need to specify the fully qualified name for your interface.

The following does the job:

    JCodeModel codeModel = new JCodeModel();
    JDefinedClass bull = codeModel._class(JMod.PUBLIC, "com.Bull", ClassType.INTERFACE);
    System.out.println("is interface " + bull.isInterface());
    codeModel.build(new File("/home/user"));
    System.out.println("done!");
    
    BufferedReader br = new BufferedReader(new FileReader("/home/user/com/Bull.java"));
    String line = null;
    while ((line = br.readLine()) != null) {
      System.out.println(line);
    }

Upvotes: 2

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