CODEWITHSUNDEEP
java
Sodex234
Sodex234

Reputation: 105

split a string Java (At certain character)

I'm trying to split a string after character 266 for instance. The user enters a string, and if its over a certain length, spit it at the (in my case) 266th char. Here is my code:

if(inputText.length() > 266){
        //Max Chars Reached. Move Some To Part 2

}

So, what I need is that it takes the 267th and on and sets that to a var(p2 for instance) and rest to p1.

Upvotes: 1

Views: 548

Answers (5)

accurate respondetur
accurate respondetur

Reputation: 702

String p1 = InputText.substring(0, 266);String p2 = InputText.substring(266);

Upvotes: 0

krzydyn
krzydyn

Reputation: 1032

Put it in a loop, sth like this:

String s="......"; //your long string
while (s.length()>266) {
   System.out.println(s.substring(0,266)); //process substring
   s=s.substring(266);  // reloop the rest
}
System.out.println(s); // process last chunk

Upvotes: 0

Rodolfo
Rodolfo

Reputation: 1171

String splited = inputText.substring(index);

// in your case
String splited = inputText.substring(266);

http://docs.oracle.com/javase/7/docs/api/java/lang/String.html#substring(int)

Upvotes: 0

deezy
deezy

Reputation: 1480

You can use substring() to split strings at specific indexes:

if(inputText.length() > 266){
        String var1 = inputText.substring(0, 267);
        String var2 = inputText.substring(267);
}

More information for Strings can be found in Javadocs.

Upvotes: 4

mszalbach
mszalbach

Reputation: 11440

Use String.substring() as descriped in the API. This allows to split a String beginning with a certain index or from an start index till an end index. See this simple example:

    public static void main(String []args){
        String myString = "Hallo";
        String part1 = myString.substring(0,2);
        String part2 = myString.substring(2);

        System.out.println(part1); //Ha
        System.out.println(part2); //llo
 }

Upvotes: 3

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