Reputation: 71
If date now is 2015-08-15. How to display the result like this:
2015-08-15
2015-08-16
2015-08-17
I have the following code:
$today = date('Y-m-d');
$a = "3";
$nextDate = date('Y-m-d', strtotime($today . ' + ' . $a . ' days'));
echo $nextDate;
Upvotes: 0
Views: 69
Reputation: 11223
$date = new DateTime();
echo $date->format('Y-m-d') . '<br/>';
for ($i = 1; $i < 3; $i++) {
$date->modify('+1 day');
echo $date->format('Y-m-d') . '<br/>';
}
Upvotes: 1